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solmaris [256]
2 years ago
10

The birth weight of the child is ___ kilograms. The child gains an average of ___ per month.

Mathematics
2 answers:
baherus [9]2 years ago
8 0

Answer:

coordinated answer: (7,7)

Andru [333]2 years ago
4 0

Answer:

3.5 kg, 0.5 kg

Step-by-step explanation:

The starting weight is represented by the y intercept, and the slope of the line is 0.5, so that's the average weight gain per month. Hope this helps!

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Cost 75.09 with a 38% markup
Sophie [7]

Answer:

103.62

Step-by-step explanation:

If I am understanding this question correctly you want the answer for how much the total would be for a 38% markup at a starter price of 75.09.

In which case it would be 103.62.

It is a 28.53 increase.

5 0
3 years ago
- 7th Grade Work -<br><br> I rlly need help ; - ;
Tanya [424]

Answer:

The length would be 1.5x + 5.

Step-by-step explanation:

So first with this, note that 2 length + 2 height gives the perimeter of the rectangle.

Given this:

2(1/2x + 4) + 2(?) = 4x+18

x+8 + 2(?) = 4x+18

2(?) = 3x+10

? = 1.5x+5

1.5x + 5 = 1.5x + 5

The length would be 1.5x + 5.

To double check, by plugging in 1.5x + 5 back into the equation for the perimeter, you will get the same perimeter:

2(1.5x + 5) + 2(1/2x+4) = P

3x+10 + x+8 = P

4x + 18 = P

8 0
3 years ago
Simplify (9 + 8 – 6)(4 – 5).
Temka [501]

Answer:

The answer would be - 11.

Step-by-step explanation:

9 + 8 = 17

17 - 6 = 11.

4 - 5 = 4 + - 5 = - 1

11(- 1) = 11 × - 1 = - 11

Therefor, your answer would be - 11.

Hope this helps!

5 0
3 years ago
Read 2 more answers
A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0
3 years ago
A carton has a length of 2 2/3, width of 1 1/3, and height of 1 1/2 feet. What is the volume of the carton?
Phantasy [73]
I hope this helps you

3 0
3 years ago
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