First, let's count mole of 10 g Calcium Carbonate
mole = Mass / Molecular Mass
Calcium Carbonate = CaCO₃
Molecular Mass = Ar Ca + Ar C + (3 x Ar O)
Molecular Mass = 40 + 12 + (3 x 16)
Molecular Mass = 100
next
Mole of CaCO₃ = 10 gram / 100
Mole of CaCO₃ = 0,1 mol
then equal the reaction equation first
CaCO₃ + 2 HCl ==> CaCl₂ + CO₂ + H₂O (Equal)
To count the mass of carbon dioxide that produced we must know the mole of CO₂ first
we can count by coefficient comparison
mole CO₂ = 
x mole CaCO₃
mole CO₂ = (1/1) x 0,1 mole
mole CO₂ = 0,1 mole
so
Mass of CO₂ = mole CO₂ x Molecular Mass of CO₂
Mass of CO₂ = 0,1 mole x (12 + (2 x 16))
Mass of CO₂ = 0,1 mole x 44
Mass of CO₂ = 4,4 g
so, mass of carbon dioxide that's produced by 10 g of calcium carbonate on reaction with chloride acid is 4,4 g.
Answer:
The space in the container so how small it is the more pressure is going to build up. YOUR WELCOME AND HAVR A GOOD DAY.
A.
H20 and OH are a conjugate acid-base pair.
Answer:
The pH of the solution is 2.77
Explanation:
Data obtained from the question include:
Concentration of hydronium ion, [H₃O⁺] = 1.7 x 10⁻³ M
pH =?
The pH is define as the measure of concentration of Hydrogen ion [H⁺] or hydronium [H₃O⁺] in an acid or a base. Mathematically, it is expressed as:
pH = –Log [H₃O⁺]
With the above equation, the pH can be obtained as follow:
pH = –Log [H₃O⁺]
[H₃O⁺] = 1.7 x 10⁻³ M
pH = –Log 1.7 x 10⁻³ M
pH = 2.77
Therefore, the pH of the solution is 2.77
Answer:
158 kg to g will give you 158,000
Explanation:
Dimensional Analysis - we find relationships between numbers and try to cross multiply.
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