Answer:
c. they carry energy is the answer
Answer:
The idea with diluting a solution is that the number of moles of solute will remain constant after the initial solution is diluted. The only ...
Explanation:
hope it helps you
Answer:
0.4mol/L
Explanation:
Data obtained from the question include:
Number of mole of NaOH(solute) = 0.20 mole
Volume of solution = 0.50 L
Molarity =.?
Molarity is simply mole of solute per unit litre of a solution. This can represented mathematically as:
Molarity = mole of solute /Volume of solution
Molarity of NaOH = 0.2mol/0.5L
Molarity of NaOH = 0.4mol/L
Answer:
- What is the limiting reactant?: HCl is the limitng reactant.
- How many moles of H₂ are formed?: 6.5 moles of H₂ are formed.
Explanation:
Part A: <em>what is the limiting reactant?</em>
1) <u>Balanced chemical equation</u>: given
- 2Al + 6HCl → 2AlCl₃ + 3H₂
2)<em> </em><u>Stoichiometric mole ratio:</u>
Use the coefficients of the balanced equation:
- 2 mol Al : 6 mol HCl : 2 mol AlCl₃ : 3H₂
3) <u>Compare the stoichiometric mole ratio of the reactants with their actual ratio</u>:
- Theoretical ratio: 2 mol Al / 6 mol HCl ≈ 0.33 mol Al / mol HCl
- Actual ratio: 6.0 mol Al / 13 mol Cl ≈ 0.46 mol Al / mol Cl
Since the actual ratio indicates that there is a greater number of moles of Al (0.46) per mol of Cl than what is required by the stoichiometric ratio(0.33), Al is in excess and HCl is the limiting reactant.
Answer: the limiting reactant is HCl.
Part B. <em>How many moles of H₂ are formed?</em>
3. <u>Determine how many moles of H₂ can be formed</u>
- Theoretical ratio using limiting reactant:
6 mol HCl / 3 mol H₂ = 13 mol HCl / x
⇒ x = 13 mol HCl × 3 mol H₂ / 6 mol HCl = 6.5 mol H₂.
The answer must be reported with two significant digits, such as the data are given.
Answer: 6.5 moles of H₂ are formed