Answer:
−0.989010989010
Step-by-step explanation:
what is the 45th term of a sequence generated by the formula tn=(-1)^n * (2n/2n+1)?
When n= 45
tn=(-1)^n*(2n/2n+1)
tn = (-1)^45 * ( 2(45) / 2(45) + 1
= -1 * 90 / (90+1)
= -90 / 91
= −0.989010989010
The 45th term of the sequence generated by the formula tn=(-1)^n*(2n/2n+1) is −0.989010989010
Answer:
(b) (c) (a)
Step-by-step explanation:
Standard Normal distribution has a higher peak in the center, with more area in this región, hence it has less area in its tails.
Student's t-Distribution has a shape similar to the Standard Normal Distribution, with the difference that the shape depends on the degree of freedom. When the degree of freedom is smaller the distribution becomes flatter, so it has more area in its tails.
Student's t-Distributionwith 1515 degrees of freedom has mores area in the tails than the Student's t-Distribution with 2020 degrees of freedom and the latter has more area than Standard Normal Distribution
52 i believe.
42 + 45 + 58 + 63 = 208
208 / 4 = 52
It simple ☺ idk how to help u. hope this ll help u understand. place ur pencil on B's dot n make it move 3 units to the right then 2 units to the up. same goes to A n C. u ll get the ans.
X= 10
Hope this helps and good luckkkk :)
