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2 years ago

PLEASE HELP SUPER SUPER SIMPLE MATH QUESTION

Mathematics

1 answer:

lilavasa [31]2 years ago

5 0

Answer:

-3 1/4

Step-by-step explanation:

12*3=36

3/12=1/4

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Help....!! I need to solve this simultaneous equation y=x-2 and y=3x+5 With working out if possible please....

Blababa [14]

Step-by-step explanation:

Y= x - 2. Y = 3x + 5

Putting value of y

x - 2 = 3x + 5

-2 - 5 = 3x - x

-7 = 2x

-7/2 = x

Putting value of x

Y = 3(-7/2) + 5

Y = - 10.5 + 5

Y = - 5.5

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3 years ago

What is the Quotient Rule for exponents?

Drupady [299]

So I think the rule is that you divide two exponents with the same base, you keep the base and subtract the powers.

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3 years ago

Raja drew a circle and labeled the center S. He used the expression 12. to find the

Aleonysh [2.5K]

Answer:a

Step-by-step explanation:

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3 years ago

The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt

Marizza181 [45]

Answer:

Exact dimensions:

$width=-1+\sqrt{7}$

$length=-1+\sqrt{7}+2$

$length=1+\sqrt{7}$

Approximate dimensions:

$width=1.64575ft$

$length=1.64575+2$

$length=3.64575ft$

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

$L=w+2$

now, we can find area

$A=L\times W$

now, we can plug it

$A=(w+2)\times w$

$A=w^2+2w$

we are given area =6

so, we can set it equal

and then we can solve for w

$w^2+2w=6$

$w^2+2w-6=0$

we can use quadratic formula

$ax^2+bx+c=0$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

$w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}$

$w=-1+\sqrt{7},\:w=-1-\sqrt{7}$

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

$width=-1+\sqrt{7}$

$length=-1+\sqrt{7}+2$

$length=1+\sqrt{7}$

Approximate dimensions:

$width=1.64575ft$

$length=1.64575+2$

$length=3.64575ft$

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3 years ago

Solve y = x2-5 for x.<br> O A. x = +/-5<br> B. X = y + 5<br> C. X = +/y+5<br> O D. x = y-5

OLEGan [10]

I got C b I’m not 100% sure

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2 years ago