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Goryan [66]
2 years ago
6

PLEASE HELP SUPER SUPER SIMPLE MATH QUESTION

Mathematics
1 answer:
lilavasa [31]2 years ago
5 0

Answer:

-3 1/4

Step-by-step explanation:

12*3=36

3/12=1/4

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Blababa [14]

Step-by-step explanation:

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Putting value of y

x - 2 = 3x + 5

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-7 = 2x

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Putting value of x

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Y = - 5.5

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3 years ago
What is the Quotient Rule for exponents?
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Raja drew a circle and labeled the center S. He used the expression 12. to find the
Aleonysh [2.5K]

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3 years ago
The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt
Marizza181 [45]

Answer:

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

L=w+2

now, we can find area

A=L\times W

now, we can plug it

A=(w+2)\times w

A=w^2+2w

we are given area =6

so, we can set it equal

and then we can solve for w

w^2+2w=6

w^2+2w-6=0

we can use quadratic formula

ax^2+bx+c=0

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

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a=1 , b=2 , c=-6

w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}

w=-1+\sqrt{7},\:w=-1-\sqrt{7}

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

width=-1+\sqrt{7}

length=-1+\sqrt{7}+2

length=1+\sqrt{7}

Approximate dimensions:

width=1.64575ft

length=1.64575+2

length=3.64575ft

7 0
3 years ago
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OLEGan [10]
I got C b I’m not 100% sure
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2 years ago
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