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11Alexandr11 [23.1K]
3 years ago
9

In which situation are waves transmitted?

Physics
2 answers:
IgorLugansk [536]3 years ago
4 0

Answer:

It's C 100% accurate.

Explanation:

marin [14]3 years ago
3 0

Answer:

In electromagnetic waves.

Explanation:

Energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels. In water waves, energy is transferred through the vibration of the water particles.

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An object exerts a reaction force when it
r-ruslan [8.4K]

Answer:

all the forces occur in pairs that if one object exerts a force on another object, then the second object exerts an equal and opposite reaction force on the first.

5 0
4 years ago
The gas in a cylinder has a volume of 5 liters at a pressure of 115 kPa. The pressure of the gas is increased to 211 kPa. Assumi
stira [4]
We know the initial pressure and volume, the final pressure, and the temperature is constant, Using the G.U.E.S.S. method we can express the problem like this:                                             
Givens: V_1=5 L, P_1= 115kPa, P_2= 211kPa

Unknown: V_2 
Equation:  \frac{V_1P_1}{P_2}=V_2
Substitute: \frac{5L*115kPa}{211kPa}= V_2
Solve: \frac{5L*115kPa}{211kPa}= 2.73 or 2.72L

      In conclusion, your answer is either 2.73 kPa if you round or 2.72 kPa if you don't. Hope you learned from it.

                                                                            
3 0
3 years ago
A mechanic uses a mechanical lift to raise a car. The car weighs 11,000 N. The lift raises the car 2.5 m.
KengaRu [80]

Potential energy = (weight) x (height)

After the car has been raised 2.5 meters, it has

                 (11,000) x (2.5) = 27,500 Joules

MORE potential energy than it had before it was lifted.

That's the energy that has to come from the work you do to lift it.

Since no mechanical process is ever 100% efficient, the work required
to accomplish this task is <em>at least  27,500 joules</em>.


5 0
3 years ago
Read 2 more answers
A uniform solid disk and a uniform hoop are placed side by side at the top of an incline of height h. If they are released from
tigry1 [53]

Answer:

The disk will reach the bottom first.

Explanation:

As we know:

change in kinetic energy = change in potential energy

                                   ΔK.E = -ΔP.E

                             \frac{1}{2} mv^{2} + \frac{1}{2}Iw^{2}  = Mgh

                                Mv^{2} +I\frac{v^{2} }{R^{2} } = 2Mgh

                           v=\sqrt{\frac{2Mgh}{M+\frac{I}{R^{2} } } }

For the disk:

I=\frac{MR^{2} }{2}

For Hoop:

I=MR^{2}

Hence

Velocity for the disk:

v=\sqrt{\frac{4}{3}gh }

Velocity for the Hoop:

v=\sqrt{gh}

8 0
3 years ago
A body weighing 108N moves with seed of 5ms–¹ in a horizontal circular path of radius 5m. Calculate the magnitude of the centrip
uysha [10]

Hi there!

Recall the equation for centripetal force;

\boxed{F_c = \frac{mv^2}{r}}

m = mass (kg)

v = velocity (m/s)

r = radius (m)

We are not given the mass directly, we are given the object's weight.

W = mg

108 = 10m \\\\m = 10.8 kg

Now, we can plug this value along with the given velocity and radius to solve:

F_c = \frac{10.8(5^2)}{5} = \boxed{54N}

8 0
3 years ago
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