A motorcycle of mass 100 kilograms slowly rolls off the edge of a cliff and falls for three seconds before reaching the bottom o
1 answer:
Answer:
2940 kg m/s
Explanation:
First of all, we need to find the final velocity of the motorcycle when it hits the ground. The horizontal component of the velocity is zero, so we can just find the vertical component, which is given by:
where
v0 =0 is the initial vertical velocity
g = 9.8 m/s^2 is the acceleration due to gravity
t = 3 s is the time of the fall
Substituting into the formula, we find
And so, we can now find the momentum of the motorcycle upon hitting the ground, which is given by the product between the mass and the velocity:
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Answer:
Explanation:
According to the free body diagram, in this case, we have:
Recall that the force of friction is given by:
Replacing and solving for the coefficient of kinetic friction:
We have an uniformly accelerated motion. Thus, the acceleration is defined as:
Finally, we calculate :
Answer:
a
The height is
b
The horizontal distance is
Explanation:
From the question we are told that
The speed is
The angle is
The height of the cannon from the ground is h = 2 m
The distance of the net from the ground is k = 1 m
Generally the maximum height she reaches is mathematically represented as
=>
=>
Generally from kinematic equation
Here s is the displacement which is mathematically represented as
s = [-(h-k)]
=> s = -(2-1)
=> s = -1 m
There reason why s = -1 m is because upward motion canceled the downward motion remaining only the distance of the net from the ground which was covered during the first half but not covered during the second half
a = -g = -9.8
So
=>
using quadratic formula to solve the equation we have
Generally distance covered along the horizontal is
=>
=>