Answer:
v = R w
With this expression we see that for each point at different radius the tangential velocity is different
Explanation:
They indicate that the angular velocity is constant, that is
w = dθ / dt
Where θ is the radius swept angle and t the time taken.
The tangential velocity is linear or
v = dx / dt
Where x is the distance traveled in time (t)
In the definition of radians
θ = s / R
Where s is the arc traveled and R the radius vector from the pivot point, if the angle is small the arc (s) and the length (x) are almost equal
θ = x / R
We substitute in the speed equation
v = d (θ R) / dt
The radius is a constant for each point
v = R dθ / dt
v = R w
With this expression we see that for each point at different radius the tangential velocity is different
Answer:
10kN
Explanation:
Given data
m1= 50kg
u1= 3m/s
m2= 100kg
u2= 6m/s
v1= 2m/s
time= 0.04s
let us find the final velocity of Bruce v1
from the conservation of linear momentum
m1u1+m2u2=m1v1+m2v2
substitute
50*3+100*6= 50*v1+100*2
150+600=50v1+200
750-200=50v1
550= 50v1
divide both sides by 50
v1= 550/50
v1=11 m/s
From
F= mΔv/t
for Bruce
F=50*(11-3)/0.04
F=50*8/0.04
F=400/0.04
F=10000
F=10kN
for Max
F=100*(6-2)/0.04
F=100*4/0.04
F=400/0.04
F=10000
F=10kN
True
Explanation:
when electrons stop.moving it cause a stoppage
in formation of magnetic field
i hope.it helps u
<span>x = 129.9 m
y = 30.9 m
First, let's calculate the horizontal and vertical velocities involved
h = 50.0cos(30) = 43.30127 m/s
v = 50.0sin(30) = 25 m/s
The horizontal distance is simply the horizontal velocity multiplied by the time, so
43.30127 m/s * 3 s = 129.9 m
So the horizontal distance traveled is 129.9 m, so x = 129.9 m
The vertical distance needs to take into account gravity which provides an acceleration of -9.8 m/s^2, so we get
d = 25 m/s * 3s - 0.5*9.8 m/s^2 * (3 s)^2
d = 75 m - 4.9 m/s^2 * 9 s^2
d = 75 m - 44.1 m
d = 30.9 m
So the vertical distance traveled is 30.9 m, so y = 30.9 m</span>
Answer:
it will option B,hope it helps