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goldenfox [79]
3 years ago
5

Una foto de 5 pulgadas de ancho y 7 pulgadas de largo se amplía a un lienzo con un ancho de 42 pulgadas. ¿Cuál será la longitud

del lienzo? Redondea la respuesta al decimal más cercano. ​
Mathematics
1 answer:
stiks02 [169]3 years ago
5 0

Answer:

jdinbdi jdidjd id

Step-by-step explanation:

idmsnd jdjdd

udjdldo xidjfbff didndkd

didjdjfofffifjfkf fifjdbjjoejdkdn

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I really need help on this!
Anvisha [2.4K]
103-12=91 so 91 i think
6 0
3 years ago
A car travels at an average speed of 56 miles per hour . how many miles does it travel in 4 hours and 15 minutes
Natali [406]

56 miles per hour

15 minutes is 1/4 of an hour

1/4 = 0.25

 so 56 x 4.25 = 238 miles

4 0
3 years ago
A collection of coins nickels and quarters is worth $1.25 . There are 13 coins in all. How many of each are there?
yulyashka [42]
3 quarters (75cents) and 10 nickels (50cents) = 1.25$
7 0
3 years ago
The manager of a pizza chain in Albuquerque, New Mexico, wants to determine the average size of their advertised 16-inch pizzas.
erastova [34]

Answer:

n=50

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=16.10 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=1.8 represent the sample standard deviation

n=25 represent the sample size  

2) Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

We need to find the degrees of freedom given by:

df=n-1=25-1=24

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=\pm 1.96

Since we assume that we are taking a bigger sample then we can replace the t distribution with the normal standard distribution, and we can assume that th population deviation is 1.8. The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =0.5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

Replacing into formula (b) we got:

n=(\frac{1.96(1.8)}{0.5})^2 =49.79 \approx 50

So the answer for this case would be n=50 rounded up to the nearest integer

5 0
3 years ago
Which job would you rather accept and what is the difference in pay, if any? Job A: $2,350 semi-monthly Job B: $2,250 bi weekly
KengaRu [80]

Answer:

job b

Step-by-step explanation:

6 0
3 years ago
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