Just solved it and the answer is D. (2,1)
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Answer and explanation:
Find attached
Both customers' arrival and service times follow exponential distribution. We have calculated the essential operating characteristics of this queuing system
Answer:
f(w) = $100 + $15*w
Step-by-step explanation:
The first $100 she deposited remain always the same, they don't change depending on the weeks. What increases along the weeks are the $15.
In the first week she will deposit $15, so she will have $100 + $15 = $115.
On the second week she will deposit $15 more, so she will have $115 + $15 = $130. Another way of writing this is $100 + $15 + $15 = $100 + $15*2.
On the third week she will have $100 + $15 + $15 + $15 = $100 + $15*3.
Therefore, after w weeks, she will have $100 + $15*w.
The function we are looking for is f(w) = $100 + $15*w
(1/3) × the cone's volume = The cylinder's volume.
Step-by-step explanation:
Step 1:
The volume of any cone is obtained by multiplying
with π, the square of the radius (
) and the height (
).
So the volume of the cone,
.
Step 2:
The cylinder's volume is nearly the same as the cone but instead by multiplying
we multiply with 1.
So the cylinder's volume is determined by multiplying π with the square of the radius of the cylinder (
) and the height of the cylinder (
).
So the the cone's volume,
.
Step 3:
Now we equate both the volumes to each other.
The cone's volume : The cylinder's volume =
=
.
So if we multiply the cone's volume with
we will get the cylinder's volume with the same dimensions.
T(n)=6-1=5
that means all terms are 5 because n does not appear on the right hand side.
However, if T(n)=6n-1, then
first term = T(1)=6(1)-1=5,
but second term T(2)=6(2)-1=11...