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Pachacha [2.7K]

3 years ago

12

The graphs of f(x) and g(x) are shown below.

1 answer:

Aleonysh [2.5K]3 years ago

5 0

Answer:

yes

Step-by-step explanation:

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Please help me A.S.A.P.

Vikentia [17]

Answer:

700 Dollars

Step-by-step explanation:

The expression for solving this is I = prt

So lets start with P, that is our principal or amount of money we start with, and we want to multiply it by our rate, or r , which is 3.5, so we would do 5000 x 0.035 to get 175, then we multiply that by our time or t, which is 4 years, so 175 x 4 = 700 dollars :D

5 0

3 years ago

Read 2 more answers

The state of Maryland charges a 6% sales tax on most merchandise sold. you purchase a new shirt for 25% how much do you pay?

Yuri [45]

If your question is 25 dollars for the shirt then the ansewer is $26.5 hope this helps.

3 0

3 years ago

Please help as soon as possible

muminat

Answer:

D, E

Step-by-step explanation:

In the table, r = 3p, and by converse, p = 1/3r. These options are D and E

7 0

3 years ago

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If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

6 0

3 years ago

Factor 2x^4 + 2x^3 - x^2 - x

MAVERICK [17]

2x^3(x+1)-x(x+1)
(2x^3-x)(x+1)
x(2x^2-1)(x+1)

8 0

3 years ago