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4 years ago

Cream from milk can be separated byprocess ......................................

Chemistry

1 answer:

pshichka [43]4 years ago

7 0

Answer:

centrifugation

Explanation:

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Answer: Velocity

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3 years ago

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kiruha [24]

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3 years ago

Arrange the following measurements, in seconds, from the greatest bias to the least bias. 6.63 ± 0.01 s, 6.6 ± 0.1 s, 6.52 ± 0.0

lord [1]

I understand here "bias" to be the uncertainty of measurements. So the order will be the following:

6.4 ± 0.5 s
<span>6.6 ± 0.1 s,
</span><span>6.63 ± 0.01 s,
</span><span>6.52 ± 0.05 s,
</span>
(notice how the second number, the one behind the symbol ± gets smaller, as the bias gets smaller).

6 0

4 years ago

what mass of copper is produce when Zinc is added to a solution containing 31.9g copper (ii) tetraoxosulphate (vi)

Sergio [31]

12.7 grams of copper will be produced.

<h3><u>Explanation</u>:</h3>

Copper is placed below zinc in the metal activity series. This means zinc can replace copper from its salt. Here zinc is added to the salt solution of copper sulphate. The reaction involved is

CuSO4 +Zn =ZnSO4 +Cu.

Zinc sulphate is soluble in the solution and rose red copper will be precipitated from the solution.

From the chemical equation we can see that 1 mole of zinc replaces 1 mole of copper. As no mass of zinc added is mentioned we will assume that excess of zinc is added.

Atomic mass of copper = 63.5

Atomic mass of sulphur = 32.

Atomic mass of oxygen = 16.

So molecular mass of copper sulphate = $63.5 + 32 + 4\times16$ = 159.5.

So, mass of 1 mole of copper sulphate is 159.5 grams.

So, in 31.9 grams of copper sulphate, number of moles of copper sulphate present = $\frac {159.5}{31.9}$ = 0.2

In 1 mole of copper sulphate, 1 mole of copper is present.

So in 0.2 moles of copper sulphate, 0.2 moles of copper is present.

So mass of 0.2 moles of copper = $0.2\times63.5$ = 12.7 grams

8 0

4 years ago

How many milliliters of concentrated hydrochloric acid solution (36.0% HCl by mass, density = 1.18 g/mL) are required to produce

poizon [28]

W=0.360
p=1.18g/mL
pH=2.12
v=14.0 L
M(HCl)=36.46 g/mol
v₀-?

1) pH=-lg[H⁺]

[H⁺]=c(HCl)=10^(-pH)

n(HCl)=v[H⁺]=v*10^(-pH)

2) n(HCl)=m(HCl)/M(HCl)=wv₀p/M(HCl)

3) v*10^(-pH)=wv₀p/M(HCl)

v₀=v*10^(-pH)M(HCl)/(wp)

v₀=14.0*10^(2.12)*36.46/(0.360*1.18)=9.115 mL

Approximately 9.1 mL of concentrated solution required.

3 0

4 years ago

Cream from milk can be separated byprocess ......................................​

Cream from milk can be separated byprocess ......................................