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Julli [10]
3 years ago
11

Plz help me it’s multiple choice (:

Biology
2 answers:
vladimir2022 [97]3 years ago
3 0

Answer:

try b

Explanation:

Sergeeva-Olga [200]3 years ago
3 0

Answer:

I believe it is C

Punnett Square.

Let me know if this helps!

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Which phenotypic change is genetic?
Westkost [7]

B. The flower color in a population changes over time.
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3 years ago
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imagine that ou are stduying a very large population of moths that is isolate d from gene flow.A single gene controls wing color
algol [13]

About the question:

I failed to find the complete question. However, I will explain why this population is considered to be in Hardy-Weinberg equilibrium, and what the destiny of the alleles is.  

Answer:

This population is in equilibrium because it accomplishes all the H-W assumptions for a population in equilibrium. Genetic nor allelic frequencies will change generation after generation. Alleles will remain equal.

Explanation:

Available data:

  • A single gene controls wing color
  • Half of the moths have white-spotted wings
  • half of the moths have plain brown wings
  • W allele is dominant and expresses white wings
  • w allele is recessive and expresses brown wings
  • Individuals mate randomly
  • No natural selection

We will know by theory if this population is or is not in equilibrium Hardy-Weinberg if the population is in concordance with the assumptions of the theory. So let us first analyze the Hardy-Weinberg assumptions for a population in equilibrium:

•  <em>Random matings:</em> Any individual get crossed with any other individual

•  <em>No superposed generations:</em> each individual can leave their gametes in the pool only once.

•  <em>No mutations: </em>No mutations originate any new gametes.

•  <em>No migration: </em>No incorporation of gametes from other populations.

•  <em>Infinite population size:</em> the probabilities of randomly taking an A gamete from the pool are p, and the probability of taking a B gamete is q.

•  <em>No natural selection:</em> Each individual has equal surviving and reproducing probabilities as any other, contributing proportionally to the gamete pool.

So, the exposed population

- is isolated, meaning that there is no gene flow from other populations. No new genes will be introduced.

- has no mutations, so no allele will change to express a new form

- individuals mate randomly

- there is no natural selection acting on this group as an evolutive force that might alter the equilibrium.

Genetic nor allelic frequencies will change generation after generation.

In a Hardy-Weinberg population, where allelic frequencies are p and q (assuming a diallelic gene), genotypic frequencies after one generation of random matings are p², 2pq and q². The allelic frequencies, as well as the genotypic frequencies, remain equal after successive generations. Alleles will remain in the population from many generations.  

5 0
3 years ago
How do cells in a meristem differ from cells in other types of plant tissue? see concept 35.2 (page 764) how do cells in a meris
mylen [45]
<span>Cells in a meristem differ from cells in other types of plant tissue differ in that they continue to divide. They are embryonic tissue that never differentiated or matured, and they give the plant the ability to grow. They are true stem cells in that they continue to divide via mitosis, and a portion of them remain undeveloped throughout the life of the plant. They are totipotent by logic, which means that any adult plant cell can be derived from them. It is this quality that allows a plant to grow new leaves if some are torn off and that scientists strive to unravel.</span>
4 0
3 years ago
In a nuclear power plant, the nuclear fuel:
iris [78.8K]
A because it’s fuel which would make it generate something.
3 0
3 years ago
Read 2 more answers
Bacteria grow in a culture at a rate proportional to the amount present. Initially, 300 strands of the bacteria are in the cultu
OLEGan [10]

Answer:

(a) number of strands (n) = time (t) ÷ proportionality constant (k)

(b) The time needed for the bacterial to double its initial size is 3.36 hours.

Explanation:

(a) Let the rate (time) be represented by t and the amount (number) of strands of bacteria be represented by n

t is proportional to n, therefore, t = kn (k is the proportionality constant)

Since t = kn, then, n = t/k

(b) Initial amount of strands = 300

Amount of strands after 2 hours = 300 + (300 × 20/100) = 300 + 60 = 360

k = t/n = 2/360 = 0.0056 hour/strand

Double of the initial size is 600 (300×2 = 600)

Time (t) needed for the bacterial to double its initial size = kn = 0.0056×600 = 3.36 hours

8 0
4 years ago
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