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2 years ago

Can someone help me with this ASAP

Mathematics

2 answers:

Andreyy892 years ago

6 0

The answer is D) angle C'D'A'.

oksian1 [2.3K]2 years ago

5 0

Answer:

Step-by-step explanation:

I did it

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Direct mail advertisers send solicitations ("junk mail") to thousands of potential customers in the hope that some will buy the

harina [27]

Answer:

The interval is (.0817, .118).

Step-by-step explanation:

Let's make this interval! The easy way is to go to STAT->TEST->A, 1-prop z-int, but I will show the long way.

1. Conditions

First we must check the conditions.

Randomization condition: The sample is given to be random, so we can assume independence.

Success/failure condition: Both np>10 and nq>10 must be met.

np = 1030(103/1030) = 103 ✓
nq = 1030(927/1030) = 927 ✓

10% condition: The sample cannot be greater than 10% of the population.

10n < N, 10(1030) < 200000 ✓

All conditions are met, so we can use a 1-proportion z-interval to represent the data.

2. Mechanics

Find $\hat{p}$ , the sample proportion.

103/1030 = .1

$\hat{q}$ , then, the probability of not p, is 1 - .1 = .9

Find z* (z star), the critical z-value.

You can do this on your calculator using 2nd->VARS->3 (or you can memorize it - it's 1.96. Winky face.) This is called the invNorm function, that takes the left side area under the normal curve. But what do we plug in to the invNorm function?

invNorm(.975) = 1.96

Plug values into the equation.

$\hat{p}$ ± z* $\sqrt{\frac{\hat{p}\hat{q}}{n} }$

.1 ± 1.96 $\sqrt{\frac{.1*.9}{1030} }$

.1 ± 1.96(.00935)

.1 - .0183 = .0817

.1 + .0183 = .118

(.0817, .118)

3. Conclusion

Based on this sample, we are 95% confident that the proportion of people the company contacts who may buy something is between .0817 and .118. That isn't very likely, but maybe they'll make a little profit!

5 0

2 years ago

2. What is 9 squared. a. 3 b. 81 C. 18 O d. 11

vitfil [10]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Quizizz 10 pts each help please WITH PIC brainiest guaranteed

lawyer [7]

Answer:

2. $-2m^4-6m^2+4m+9$

3. $-2m^4-6m^2-4m+9$

Step-by-step explanation:

In general we can write a polynomial in standard form as

$ax^n+bx^n^-^1+cx^n^-^2+...+px+q$

Given $4m-2m^4-6m^2-4m+9$

Combine the like terms: 4m and -4m

4m-4m=0

We have 4m-4m=0

So, write the remaining terms

$-2m^4-6m^2+9+0$

= $-2m^4-6m^2+9$

This is in decreasing order of powers.

Hence the answer is the standard form is

$-2m^3-6m^2+9$

But in the given options, you can choose option 2 and option 3 are in standard form.

Because they are in decreasing order of powers.

In other two options, the constants term is first and the highest power term is at the last. So, they are not in standard form.

-2m^4-6m^2+4m+9

-2m^4-6m^2-4m+9

I hope this helps you.

And please comment if I need to do corrections.

Please let me know if you have any questions.

8 0

2 years ago

Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$