Question

5. Calculate the time required to deposit 0.37g of Silver from a silverNitrate solution using a current of 2.5A( Charge of Ag in AgNO3 is + 1)​

Answer 1

Time required : 132.2 s

Further explanation

Given

mass of Silver = 0.37 g

current = 2.5 A

Required

time do deposit

Solution

Faraday's Law :

$\tt W=\dfrac{e.i.t}{96500}$

e = ar/valence (valence Ag = 1)

i = current

t = time = s

$\tt 0.37~g=\dfrac{108/1\times 2.5~A\times t }{96500}\\\\t=132.2~s$