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Dennis_Churaev [7]
3 years ago
7

5. Calculate the time required to deposit 0.37g of Silver from a silverNitrate solution using a current of 2.5A( Charge of Ag in

AgNO3 is + 1)​
Chemistry
1 answer:
Monica [59]3 years ago
8 0

Time required : 132.2 s

<h3>Further explanation</h3>

Given

mass of Silver = 0.37 g

current = 2.5 A

Required

time do deposit

Solution

Faraday's Law :

\tt W=\dfrac{e.i.t}{96500}

e = ar/valence (valence Ag = 1)

i = current

t = time = s

\tt 0.37~g=\dfrac{108/1\times 2.5~A\times t }{96500}\\\\t=132.2~s

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