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irinina [24]
3 years ago
5

How do you know that a bowling ball is a soild

Chemistry
1 answer:
julsineya [31]3 years ago
4 0
It holds its own shape and it’s solid
You might be interested in
A series circuit has two 5.0-ohm resistors and a power source of 9.0 volts. How will the current be affected and what will it be
miskamm [114]
The formula for solving current given with resistance and power source or voltage is shown below:
I = V/R  

When two 5 ohms resistors are in series, we have:
I = 9 volts / (5+5 ohms)
I = 0.9 amperes

When it is being added with another 7.5 resistors, we have:
I = 9 volts / (5+5+7.5 ohms)
I = 0.529 ampere

The answer to the question is the letter "D. decrease; 0.51 amps".
3 0
3 years ago
Consider the following equilibrium: 2SO^2(g) + O2(9) = 2 SO3^(g)
saul85 [17]

Answer:

At equilibrium, the forward and backward reaction rates are equal.

The forward reaction rate would decrease if \rm O_2 is removed from the mixture. The reason is that collisions between \rm SO_2 molecules and \rm O_2\! molecules would become less frequent.

The reaction would not be at equilibrium for a while after \rm O_2 was taken out of the mixture.

Explanation:

<h3>Equilibrium</h3>

Neither the forward reaction nor the backward reaction would stop when this reversible reaction is at an equilibrium. Rather, the rate of these two reactions would become equal.

Whenever the forward reaction adds one mole of \rm SO_3\, (g) to the system, the backward reaction would have broken down the same amount of \rm SO_3\, (g)\!. So is the case for \rm SO_2\, (g) and \rm O_2\, (g).

Therefore, the concentration of each species would stay the same. There would be no macroscopic change to the mixture when it is at an an equilibrium.

<h3>Collision Theory</h3>

In the collision theory, an elementary reaction between two reactants particles takes place whenever two reactant particles collide with the correct orientation and a sufficient amount of energy.

Assume that \rm SO_2\, (g) and \rm O_2\, (g) molecules are the two particles that collide in the forward reaction. Because the collision has to be sufficiently energetic to yield \rm SO_3\, (g), only a fraction of the reactions will be fruitful.

Assume that \rm O_2\, (g) molecules were taken out while keeping the temperature of the mixture stays unchanged. The likelihood that a collision would be fruitful should stay mostly the same.

Because fewer \!\rm O_2\, (g) molecules would be present in the mixture, there would be fewer collisions (fruitful or not) between \rm SO_2\, (g) and \rm O_2\, (g)\! molecules in unit time. Even if the percentage of fruitful collisions stays the same, there would fewer fruitful collisions in unit time. It would thus appear that the forward reaction has become slower.

<h3>Equilibrium after Change</h3>

The backward reaction rate is likely going to stay the same right after \rm O_2\, (g) was taken out of the mixture without changing the temperature or pressure.

The forward and backward reaction rates used to be the same. However, right after the change, the forward reaction would become slower while the backward reaction would proceed at the same rate. Thus, the forward reaction would become slower than the backward reaction in response to the change.

Therefore, this reaction would not be at equilibrium immediately after the change.

As more and more \rm SO_3\, (g) gets converted to \rm SO_2\, (g) and \rm O_2\, (g), the backward reaction would slow down while the forward reaction would pick up speed. The mixture would once again achieve equilibrium when the two reaction rates become equal again.

5 0
2 years ago
A gas exerts a pressure of 350.0 torr at 20.0 Celsius. What would be the new pressure in atmospheres if the temperature is raise
IgorC [24]

Answer:

373.88 torr

Explanation:

P1 = 350 torr

T1 = 20°C = (20 + 273.15)K = 293.15K

P2 = ?

T2 = 40°C = (40 + 273.15)K = 313.15K

From pressure law,

Pressure of a given mass of gas is directly proportional to its temperature.

P = KT

K = P / T

P1 / T1 = P2 / T2

Solve for P2

P2 = (P1 * T2) / T1

P2 = (350 * 313.15) / 293.15

P2 = 109602.5 / 293.15

P2 = 373.878 torr

P2 = 373.88 torr

The new pressure of the gas would be 373.88 torr.

5 0
3 years ago
Read 2 more answers
1)Define potential Energy.
Margarita [4]

1. Potential Energy is stored energy a object has when it's not moving.

2. Potential Energy is it's highest on the first stage because as you see the roller coaster is bout to go down the tract which is going to higher the kinetic energy and lower the potential energy.

3. Kinetic Energy is the amount of energy a object has when it's in motion or moving.

4. Kinetic Energy is it's highest in the third stage after it's gone down the tract and potential energy fully decreased and it's at zero.

Remember that potential energy is stored energy so when a object is not moving in this case the roller coaster isn't moving on the first stage when its bout to go down the roller coaster. Kinetic energy is the amount of energy a object has when it's in motion so in this case the third stage would have the highest example of Kinetic energy because it's fully in motion and has no potential energy.

4 0
3 years ago
a rectangular piece of aluminum foil measures 13.72 cm x 8.63 cm and has a mass of 3.1 g. Find how thick it is
Leona [35]

The two dimensions of aluminum foil are given 13.72 cm and 8.63 cm respectively with mass  3.1 g.

The density of aluminum is 2.7 g/cm^{3}. It is defined as mass per unit volume thus, volume of aluminum can be calculated as follows:

V=\frac{m}{d}

Putting the values.

V=\frac{3.1 g}{2.7 g/cm^{3}}=1.148 cm^{3}

The volume of cuboid is l\times b\times h, the length and breadth are given, height can be calculated as follows;

h=\frac{V}{l\times b}

Putting the values,

h=\frac{1.148 cm^{3}}{(13.72 cm)(8.63 cm)}=0.009695 cm

Or, approximately 9.7\times 10^{-3}cm

Therefore, thickness of aluminum foil is 9.7\times 10^{-3}cm

7 0
3 years ago
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