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viktelen [127]
3 years ago
13

What process takes place before an article is published in a scientific journal/

Chemistry
1 answer:
Goshia [24]3 years ago
7 0
Before an article is published in a scientific journal or in any "peer-reviewed" journal the article is reviewed thoroughly by scholars from the journal as well as peers or scholars of the articles author from the same field. This process occurs to provide credibility to the ideas being published and so that readers and other scholars can rely on the validity of the material being published. 
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100 ml is drawn from 0.1 M solution of KCl and added to 900 ml of water. What is the
grandymaker [24]

Answer:

The new concentration will be 0.01 M.

Explanation:

To determine the new concentration we use the following formula.

concentration (1) × volume (1) = concentration (2) × volume (2)

concentration (1) = 0.1 M

volume (1) = 100 mL

concentration (2) = unknown

volume (2) = 100 mL + 900 mL = 1000 mL

concentration (2) = [concentration (1) × volume (1)] / volume (2)

concentration (2) = (0.1 × 100) / 1000 = 0.01 M

3 0
2 years ago
Label each transition in this flow chart as a chemical change or a physical change
Elodia [21]

1) Left up: a chemical change. We can see new substance (red-blue) is formed from one blue and one red atom.

In chemical change new substances are formed, the atoms are rearranged and the reaction is followed by an energy change.

2) Left down: a chemical change. We can see new substance (red-blue) is formed from two blue and one red atoms.

3) MIddle: a physical change. There is no new substance. Bonds are not broken.

4) Right up: a chemical change. Bonds are broken.

5) Right down: a physical change. Change of state of matter.

4 0
3 years ago
Calculate the hydronium ion concentration in an aqueous solution with a ph of 9.85 at 25°c.
UkoKoshka [18]

Answer:

1.41 × 10⁻¹⁰ M

Explanation:

We have a solution with a pH of 9.85 at 25 °C. We can calculate the concentration of H⁺ using the following expression.

pH = -log [H⁺]

[H⁺] = antilog -pH

[H⁺] = antilog -9.85

[H⁺] = 1.41 × 10⁻¹⁰ M

H⁺ is usually associated with water molecules forming hydronium ions.

H⁺ + H₂O → H₃O⁺

Then, the concentration of H₃O⁺ ions is 1.41 × 10⁻¹⁰ M.

8 0
3 years ago
Read 2 more answers
____ is converted to carbohydrate by plants during photosynthesis.
Ratling [72]
Carbon dioxide 
Have a great day:)
5 0
3 years ago
Read 2 more answers
When 125 mL of 0.150 M Pb(NO3)2 is mixed with 145 mL of 0.200 M KBr, 4.92 g of PbBr2 is collected. Calculate the percent yield.
Semenov [28]

Answer:

Y = 92.5 %

Explanation:

Hello there!

In this case, since the reaction between lead (II) nitrate and potassium bromide is:

Pb(NO_3)_2+2KBr\rightarrow PbBr_2+2KNO_3

Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:

0.125L*0.150\frac{molPb(NO_3)_2}{L} *\frac{1molPbBr_2}{1molPb(NO_3)_2} =0.01875molPbBr_2\\\\0.145L*0.200\frac{molKBr}{L} *\frac{1molPbBr_2}{2molKBr} =0.0145molPbBr_2

Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:

0.0145molPbBr_2*\frac{367.01gPbBr_2}{1molPbBr_2} =5.32gPbBr_2

And the resulting percent yield:

Y=\frac{4.92g}{5.32g} *100\%\\\\Y=92.5\%

Regards!

4 0
3 years ago
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