Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
9x^2 + 4x^3
Hope this helped
Lets solve all of these:-
#1
√361 = 361 · 2
?
√361 = 361 · 2
√361 = 19
361 · 2 = 722
19 ≠ 722
So this equation is not true
#2:-
√361 = 19²
?
√361 = 19²
√361= 19
19² = 19 · 19 = 361
19 ≠ 361
So this equation is not true
√361 = 361 ÷ 2
?
√361 = 361 ÷ 2
√361 = 19
361 ÷ 2 = 180.5
√361 ≠ 361 ÷ 2
So this equation is not true
√361 = √19²
√361 = 19
√19² = 19
19 = 19
SO the last one is right. Hope I helped ya!! xD
There something you ain’t giving us in this equation