Design an experiment to demonstrate phototropism.
1 answer:
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Answer:
1: At temperatures below 542.55 K
2: At temperatures above 660 K
Explanation:
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In this case, according to the thermodynamic definition of the Gibbs free energy, it is possible to write the following expression:
Whereas ΔG=0 for the spontaneous transition. In such a way, we proceed as follows:
1:
It means that at temperatures lower than 542.55 K the reaction will be spontaneous.
2:
It means that at temperatures higher than 660 K the reaction will be spontaneous.
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