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2 years ago

What is the main difference between a proton and a neutron?

Chemistry

2 answers:

Olenka [21]2 years ago

5 0

I’m pretty sure it’s B since ones charge the neutral while ones is positive, it’s an obvious difference as well/

NeX [460]2 years ago

5 0

Answer:

b. Charge is the main difference

Explanation:

This is a theory question which you just need to understand and remember the concepts.

Protons and neutrons are relatively the same sizes.

The charges here are defined, protons are positively charged and neutrons have no charge (electrically neutral).

Both are located in the nucleus of an atom.

Proton radiation rarely occurs and neutron radiation is a form of ionizing radiation in cases typically of nuclear fission or nuclear fusion.

The most likely answer is that the charge is the main difference. This is also a basic concept so this would be the answer.

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True or false? All producers are at the top of the food web

Korvikt [17]

Answer:

false all producers are at the top of food web

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2 years ago

the student measured the volume of water as 80.0 mL. she discovered that the actual volume was 80.1 mL. is her results ac urate

Oksana_A [137]

Yes, the more decimal places in a number mean that it is more accurate :3

8 0

3 years ago

Read 2 more answers

The envelope of air that surrounds the earth is called

svlad2 [7]

Atmosphere is the envelope of air that surrounds the earth.

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2 years ago

A sample of hydrogen gas at a pressure of 977 mm Hg and a temperature of 32 °C, occupies a volume of 11.3 liters. If the gas is

IrinaK [193]

Answer : The volume of gas sample will be, 9.93 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles of gas.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=11.3L\\T_1=32^oC=(32+273)K=305K\\V_2=?\\T_2=-5^oC=(-5+273)K=268K$

Now put all the given values in above equation, we get:

$\frac{11.3L}{305K}=\frac{V_2}{268K}\\\\V_2=9.93L$

Therefore, the volume of gas sample will be, 9.93 L

6 0

3 years ago

he equation represents the combustion of sucrose. C12H22O11 + 12O2 12CO2 + 11H2O If there are 10.0 g of sucrose and 8.0 g of oxy

xeze [42]

Answer:

The moles of sucrose that are available for this reaction is 0.0292 moles

Explanation:

Combustion is an specifyc reaction where the reactants react with O₂ in order to produce CO₂ and H₂O

This combustion is: C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O

We have to conver the mass to moles, to find out the limiting reactant

10 g . 1 mol / 342 g = 0.0292 moles of sucrose

8 g . 1mol / 32g = 0.250 moles of O₂

The moles of sucrose that are available for this reaction is 0.0292 moles

Before we start to work with the equation we must find the limiting reactant. When you find it, you can do all the calculations.

6 0

3 years ago