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3 years ago

What is the main difference between a proton and a neutron?

Chemistry

2 answers:

Olenka [21]3 years ago

5 0

I’m pretty sure it’s B since ones charge the neutral while ones is positive, it’s an obvious difference as well/

NeX [460]3 years ago

5 0

Answer:

b. Charge is the main difference

Explanation:

This is a theory question which you just need to understand and remember the concepts.

Protons and neutrons are relatively the same sizes.

The charges here are defined, protons are positively charged and neutrons have no charge (electrically neutral).

Both are located in the nucleus of an atom.

Proton radiation rarely occurs and neutron radiation is a form of ionizing radiation in cases typically of nuclear fission or nuclear fusion.

The most likely answer is that the charge is the main difference. This is also a basic concept so this would be the answer.

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CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7

padilas [110]

Answer: The $\Delta G$ for the reaction is 54.425 kJ/mol

Explanation:

For the given balanced chemical equation:

$CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)$

We are given:

$\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol$

To calculate $\Delta G^o_{rxn}$ for the reaction, we use the equation:

$\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]$

For the given equation:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J$

Conversion factor used = 1 kJ = 1000 J

The expression of $K_p$ for the given reaction:

$K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}$

We are given:

$p_{COCl_2}=0.735atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.185atm$

Putting values in above equation, we get:

$K_p=\frac{(0.735)^2}{0.410\times 0.185}\\\\K_p=20.85$

To calculate the gibbs free energy of the reaction, we use the equation:

$\Delta G=\Delta G^o+RT\ln K_p$

where,

$\Delta G$ = Gibbs' free energy of the reaction = ?

$\Delta G^o$ = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = $8.314J/K mol$

T = Temperature = $25^oC=[25+273]K=298K$

$K_p$ = equilibrium constant in terms of partial pressure = 20.85

Putting values in above equation, we get:

$\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(20.85))\\\\\Delta G=54425.26J/mol=54.425kJ/mol$

Hence, the $\Delta G$ for the reaction is 54.425 kJ/mol

7 0

3 years ago

What happens when sugar disolves in water?

Elis [28]

First, the sugar dissolves into small sugar molecules, Then fills in the spaces in between the water molecules thus, making Sugar water.

I hope that answered your question and has come to your help.

4 0

4 years ago

Read 2 more answers

Which of the following is not an example of a pure element? Ar CO,2 O,2

KatRina [158]

O,2
hopefully that helps lol if u have any more questions like that don't be afaid to ask me

7 0

3 years ago

Compounds usually have the same properties as the bonds they are made from true or false

gavmur [86]

Well , I will say this is a false statement.
This is because compounds which were all made by the same bond have same physical properties but different chemical properties.

Chemical Properties :
How do the subtances react with ( water, acid,alkaline, base , gas like oxygen, etc. )

Physical Properties :
- Solubility of those subtances in (water or organic solvent )
- Electric Conductivity
- Melting or Boiling Point
- Density
- Smell (exp : Ammonia has pungent smell , Esters has fruity smell)

8 0

3 years ago

Write the chemical equation for the reaction whose enthalpy change is the standard enthalpy of formation of fructose, C6H12O6(s)

ziro4ka [17]

Answer:

$6 C(s) + 6_{H2}(g) + 3_{O2}(g)$