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Bingel [31]
3 years ago
13

Write the slope-intercept form of the equation of the line described.

Mathematics
1 answer:
Zina [86]3 years ago
7 0

Answer:

Slope intercept form: y=mx+b; where m is the slope and B is the y intercept

For 2 lines to be parallel they must have the same slope. Thus, the slope of the new line is going to be 1.

To find the y intercept plug in the slope and the x, y into the equation y=mx+b:

y=mx+b

y=1x+b

2=1(2)+b

2=2+b

0=b

b=0

Now that we have your slope and y intercept we can make the equation:

y=1x+0

y=x

Step-by-step explanation:

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\begin{gathered}\boxed{\begin{array}{c|c}\boxed{\bf Form} &\boxed{\bf Equation} \\ \sf Slope\: intercept\:form &\sf y=mx+b \\ \sf Intercept\:form &\sf \dfrac{x}{a}+\dfrac{y}{b}=1\\ \sf Normal\:form &\sf xcos\omega+ysin\omega=p \\ \sf Two\: point\:form &\sf y-y_1=\left(\dfrac{y_2-y_1}{x_2-x_1}\right)(x-x_1)\\ \sf Point\:slope\:form &\sf y-y_1=m(x-x_1) \\ \sf Standard\:form &\sf Ax+By+C=0 \end{array}}\end{gathered}

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