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mash [69]
3 years ago
7

I NEED HELP PLEASE !!!

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer: Because \frac{\pi }{3} =\frac{180\°}{3} =60\°, therefore \frac{\pi }{3} =60\°.

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Social studies Geometry P.11 Similarity and altitudes in right triangles CEZ You have priz If SU = 28 and UV = 6, what is TU? T
Alex777 [14]

Answer:

TU ≈ 12.96

Step-by-step explanation:

Using the Altitude on Hypotenuse theorem

(leg of outer triangle)² = (part of hypotenuse below it) × (whole hypotenuse)

TU² = UV × SU = 6 × 28 = 168 ( take square root of both sides )

TU = \sqrt{168} ≈ 12.96 ( to the nearest hundredth )

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3 years ago
68.76 rounded to the nearest whole number
Ahat [919]
68,76 rounded to the nearest whole number will be equal 69 

hope this will help you 
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PLEASE HELP PICTURE IS SHOWM
katrin2010 [14]
Congruent since all angles are equivalent to each other.
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3 years ago
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Hi there,

x(x + 19) = -34

I'm going to solve your equation step-by-step.<span><span>x<span>(<span>x + 19</span>) </span></span>= <span>−34

</span></span>Step 1: Simplify both sides of the equation.<span><span><span>x2 </span>+ <span>19x </span></span>= <span>−34

</span></span>Step 2: Subtract -34 from both sides.<span><span><span><span>x2 </span>+ <span>19x </span></span>− <span>(<span>−34</span>) </span></span>= <span><span>−34 </span>− <span>(<span>−34</span>)

</span></span></span><span><span><span><span>x2 </span>+ <span>19x </span></span>+ 34 </span>= 0

</span>Step 3: Factor left side of equation.<span><span><span>(<span>x + 2</span>) </span><span>(<span>x + 17</span>) </span></span>= 0

</span>Step 4: Set factors equal to 0.<span><span><span>x + 2 </span>= <span><span><span>0<span> or </span></span>x </span>+ 17 </span></span>= 0

</span><span><span>x = <span>−<span><span>2<span> or </span></span>x </span></span></span>= <span>−17

</span></span>Answer:<span><span>x = <span>−<span><span>2<span> or </span></span>x </span></span></span>= <span>−<span>17

Hope this helps! :)</span></span></span>
5 0
3 years ago
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How do you do this? algebra II
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