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3 years ago

Complete the missing parts of the paragraph proof.

Mathematics

1 answer:

lianna [129]3 years ago

6 0

Answer:

1) angle 1 is congruent to angle 3

2) angle 2

3) angle 3

4)....

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83 simplified<br> whoever gets it right is the brainliest

Alina [70]

83 is a whole number and cannot be simplified.

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4 years ago

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Elizabeth has 1 7/10 as many plants as Rosalie has in her arden. If Elizabeth has 51 plants, how many plants does Rosalie have i

dexar [7]

Question: Elizabeth has 1 7/10 as many plants as Rosalie has in her garden. If Elizabeth has 51 plants, how many plants does Rosalie have in her garden?

Answer: X=30

explanation:

1 7/10 can be rewritten as 1.7

x=amount of plants that Rosalie has

x=1.7/51

x=30

question answered by

(jacemorris04)

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3 years ago

Broccoli costs $1.50 PER POUND at a grocery store. How much money does 64 OUNCES of broccoli cost?

Gnoma [55]

$6.00
Show your work in the attachment. Down below

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4 years ago

Help plessseeee I can’t get the answer

ivanzaharov [21]

The answer you put in is y = 1/2 + 4

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3 years ago

Suppose that, after measuring the duration of many telephone calls, a telephone company found their data was well-approximated b

Musya8 [376]

Answer:

a) 7.79%

b) 67.03%

c) Cumulative Distribution Function

$P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b$

Step-by-step explanation:

We are given the following in the question:

$p(x) = 0.1 e^{-0.1x}$

where x is the duration of a call, in minutes.

a) P( calls last between 2 and 3 minutes)

$=\displaystyle\int^3_2 p(x)~ dx\\\\= \displaystyle\int^3_20.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^3_2\\\\=-\Big[e^{-0.3}-e^{-0.2}\Big]\\\\= 0.0779\\=7.79\%$

b) P(calls last 4 minutes or more)

$=\displaystyle\int^{\infty}_4 p(x)~ dx\\\\= \displaystyle\int^{\infty}_40.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^{\infty}_4\\\\=-\Big[e^{\infty}-e^{-0.4}\Big]\\\\=-(0- 0.6703)\\= 0.6703\\=67.03\%$

c) cumulative distribution function

$P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b$

6 0

4 years ago