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Bumek [7]
3 years ago
11

Jess needs 4 ounces of cheese for every 10 ounces of meat in a recipe if she uses 30 ounces of meat how much cheese will she nee

d?
PLEASE ANSWER!
Mathematics
1 answer:
Sphinxa [80]3 years ago
6 0

Answer:

12 ounces of cheese

Step-by-step explanation:

Set the ratio of the ounces of cheese : meat (which is 4 : 10). If Jess uses 30 ounces of meat, all we need to do is compare the amounts to each other, using the variable <em>x:</em>

4 : 10

<em>x</em> : 30

We can see that there is 3 times the amount of meat required than there was in the original recipe. Because of this, all we need to do is multiply the ounces of cheese by 3. This leaves:

(4 : 10) * 3 = 12 : 30

When we look at the ratio we made (<em>x</em> : 30), we can see that x = 12.

Don't forget the units when answering the question!

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Read 2 more answers
The combined area of a square and a rectangle is 225 square yards. the length of the rectangle is 8 times the width of the recta
snow_lady [41]

Answer:

The rectangle:  <u>L = 40 yards.   W = 5 yards</u>

The square: The length and width are both <u>5 yards</u>.

Step-by-step explanation:

<u>Let L and W be the length and width of the rectangle. </u>

<u>Let l and w be the length and width of the square.</u>

Area for each is:

Rectangle:  L*W

Square:       l*w

We are told that <u>L*W + l*w = 225 yards^2</u>

We are also told that

<u>L = 8W </u>

and that

<u>l = W</u>

Since the sides of a square are all equal, w is also W:  <u>w=W</u>

Summarizing and substituting:

L*W + l*w = 225 yards^2

(8W)*W + W*W = 225 yards^2

8W^2 + W^2 = 225 yards^2

9W^2  = 225 yards^2

W^2 = 25

W = 5 feet

---------------------

Therefore, since L = 8W <u>,</u> <u>L = 40 yards.   W = 5 yards</u> for the rectangle.

The square:  l=W, so <u>l = 5 yards, and thus w=5 yards</u>

--------------------------

Check:

Do a rectangle of 40' x 5' plus a square of 5' x 5' have a total combined area of 225 yards^2?

40yd x 5yd + 5yd x 5yd = 225 yards^2?

200 yd^2 + 25 yd^2 = 225 yards^2?

YES

5 0
2 years ago
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