The answer is use Photomath
Multiply 2 by 1/2 to get 1.
Multiply 1 by 2/3 to get 2/3.
Multiply 2/3 by 3/4 to get 6/12 = 1/2.
Multiply 1/2 by 4/5 to get 4/10 = 2/5.
Multiply 2/5 by 5/6 to get 10/30 = 1/3.
Multiply 1/3 by 6/7 to get 6/21 = 2/7. (I suspect there's a typo in the question.)
And so on, so that the <em>n</em>th term in the sequence is multiplied by <em>n</em>/(<em>n</em> + 1) to get the (<em>n</em> + 1)th term.
Recursively, the sequence is given by

We can solve this exactly by iterating:

and so on down to

or

and with lots of cancellation, we end up with

Answer:
3x +y = 13
Or, x=13-y/3......eqn(i)
Now putting the value of x
2x - y = - 1
Or, 2(13-y/3) - y = - 1
Or, 26 - 2y /3 - y = -1
Or, 26 - 2y - 3y = - 3
Or, 26 - 5y = - 3
Or, - 5y = - 3 - 26
Or,y = - 39/ (- 5)
Or, y = 7.8~
Return is the answer. That's the gain or loss returned from the investment.
X² + xy - 2x - 2y
The first thing would be to break the polynomial up into pairs.
(x² + xy) + (-2x -2y)
Then you can factor them individually.
(x² + xy)
Both numbers have x in common, so you can factor it out and get
x(x + y)
Then you factor the other pair,
(-2x -2y)
Both numbers have -2 in them, so you can factor it out and get
-2(x + y)
Now your two pairs are
[x (x + y)] and [-2 (x + y)]
Notice that the two terms in parentheses are the same, so you can get rid of one and combine the two outside terms to get a final answer of
(x - 2)(x + y)