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Rainbow [258]
2 years ago
9

Find the mean for the amounts: $17,483; $14,983; $13,592; $14,600; $18,540; $14,993

Mathematics
1 answer:
Dimas [21]2 years ago
4 0

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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7 0
2 years ago
Solve the following equation: 10 = -4 x
defon
I think it's x= -2.5

10/-4= -4x/-4

You need to get x by itself so you need to divide 4 in each side . Shown above

5 0
3 years ago
Find the equation of the straight line which passes through each of the following pairs of points.
Tems11 [23]

Answer:

y = 3x + 1

Step-by-step explanation:

First, find slope:

y2 - y1 / x2 - x1

10 - 4/ 3 - 1 = 6 / 2 = 3

Then, put the equation into point-slope form using the point (1, 4):

y - y1 = m(x - x1)

where m is the slope

y - 4 = 3(x - 1)

If you want to put this into slope-intercept form, it would be

y-4=3(x-1)\\y - 4 = 3x - 3\\y = 3x + 1

4 0
2 years ago
Item 4
kogti [31]

Answer:

he is an ordinary man because that is what the speaker is talking about

5 0
3 years ago
Read 2 more answers
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
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