Answer:
27
Step-by-step explanation:
Let the two numbers, smaller be x and larger be y.
As per statement, one number is 3 less than a second number.
x = y - 3…Eq..1
Twice the second number is 3 less than 3 times the first.
3x = 2y + 3…Eq..2
Now putting the value of x from Eq..1 to Eq…2
3x = 2y + 3
3 (y - 3) = 2y + 3
3y - 9 = 2y + 3
3y - 2y = 3 + 9
y = 12
The larger number is 12.
Now putting the value of y in Eq. 1 to get the value of x
x = y - 3
x = 12 - 3
x = 9
The smaller number is 9
Answer the two numbers, smaller is 9 and larger is 12.
To check the correctness of answer, substituting the derived values of two numbers in the Eq…2
3x = 2y + 3
3 × 9 = 2 × 12 + 3
27 = 24 + 3
27 =27
I simplified it and I got 36
It would be 16 meters long
The first inequality is represented by the line with the y intercept of 100 (the "top" line). We need to pick a region that satisfies the inequality. Let's try the point (0, 0). If we sub in 0 for x and 0 for y, the inequality would look like this: 0 + 0 < 100. Is 0 less than 100? Yes of course it is. So the regoins that satisfy that inequality are regions 1 and 2. Now for the second inequality. Obviously, it is the other line, the "bottom" line with the y intercept of 50. If we sub in the same point of (0, 0), subbing in looks like this: 0 + 2(0) > 100. Is 0 greater than 100? Of course it's not. So the regions that satisfy this inequality are regions 2 and 3. The solution to an inequality is where the shading overlaps. For us that is in region 2 only. Your choice for the answer is c
