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2 years ago

The diagram below shows the energy conversions of the Krebs cycle, which is part of cellular respiration. The U-shaped

Chemistry

2 answers:

Jobisdone [24]2 years ago

8 0

The answer to your problem is B

SVEN [57.7K]2 years ago

5 0

Answer:

Explanation:

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Mass x height x gravity is the formula to calculate:

Sindrei [870]

Answer:

Potential energy

Explanation:

$p.e = mgh$

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2 years ago

How does your body get the energy that it needs to do all of its daily activities? Describe the energy conversion that take plac

Mama L [17]

IF you are fat like your mom well i don't know

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2 years ago

5. Can you determine the number of neutrons in the nucleus of an atom by looking at the element's average atomic mass and the at

Shkiper50 [21]

Answer:

No you can't

Explanation:

The atomic number is the amount of protons in element's nucleus, that's one reason why. The second reason is that the atomic mass is protons and neutrons combined, their estimated value, which doesn't show how much neutrons are in an element. It does show combined, but not specifically neutrons

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2 years ago

Which of the following is the BEST description of a budget? *<br> 10

Nonamiya [84]

Answer:

A budget is an estimation of revenue and expenses over a specified future period of time and is usually compiled and re-evaluated on a periodic basis. Budgets can be made for a person, a group of people, a business, a government, or just about anything else that makes and spends money.

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2 years ago

A phosphate buffer is involved in the formation of urine. The developing urine contains H2PO4 and HPO42- in the same concentrati

Katen [24]

Answer:

The ionization equation is

$H_{2}PO_{4}^{-} +H_{2}O$ ⇄ $HPO_{4}^{-2} +H_{3}O^{+}$ (1)

Explanation:

The ionization equation is

$H_{2}PO_{4}^{-} +H_{2}O$ ⇄ $HPO_{4}^{-2} +H_{3}O^{+}$ (1)

As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.

The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,

$Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}$

The pKa is

$-Log (Ka) = -Log (6.2x10^{-8}) = 7.2$

The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.

In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.

If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1) moves to the left neutralizing the excess proton concentration.

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3 years ago