Answer : The final temperature of the aluminum and ethylene glycol is
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of aluminum =
= specific heat of ethylene glycol =
= mass of aluminum = 13.60 g
= mass of ethylene glycol = 23.27 g
= final temperature of aluminum and ethylene glycol = ?
= initial temperature of aluminium =
= initial temperature of ethylene glycol =
Now put all the given values in the above formula, we get:
Therefore, the final temperature of the aluminum and ethylene glycol is
Answer:
Skeletal
Cardiac
Smooth
Explanation:
The body contains three types of muscle tissue: skeletal muscle, cardiac muscle, and smooth muscl
Answer:
(a) HCl is the limiting reactant.
(b) 28.45 g
(c) 19.10 g.
Explanation:
(a) 4HCL(aq) + MnO2(s) ----> MnCl2(aq) + 2H2O(l) + Cl2(g)
Using the relative atomic masses:
4 * (1.008 + 35.45( g of HCl react with (54.983 + 2*15.999) g of MnO2.
145.832 g HCl reacts with 86.981 g MnO2.
So 47.7 g HCl reacts with (86.981 / 145.832) * 47.7 = 28.451 g MnO2.
We have 42.5 g of MnO2 so HCl is the limiting reactant.
(b) The theoretical yield of Cl2 is (70.9 /86.981) * 28.451 = 23.91 g.
(c) The actual yield of chlorine is 23.91 * 0.799 = 19.10 g.
Answer:
NaOH + HCl —> NaCl + H₂O
Explanation:
From the question given above, we obtained the following equation:
4NaOH + 4HCl —> NaCl + H₂O
The equation can be balance as follow:
4NaOH + 4HCl —> NaCl + H₂O
There are 4 atoms of Na on the left side and 1 atom on the right side. It can be balance by putting 4 in front of NaCl as shown below:
4NaOH + 4HCl —> 4NaCl + H₂O
There are a total of 8 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of H₂O as shown below:
4NaOH + 4HCl —> 4NaCl + 4H₂O
Next, divide through by 4 to express the equation with the lowest coefficients.
NaOH + HCl —> NaCl + H₂O
Now the equation is balanced.
NOTE: Smallest coefficients are always used to represent a balanced equation.