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V125BC [204]
3 years ago
10

Is blood a solution ?

Chemistry
1 answer:
qaws [65]3 years ago
6 0
A blood solution is where Blood is a colloidal solution with partial behavior of a suspension! And it belongs to the non-newtonian liquids! VERY IMPORTANT INFO: Colloides do not exist freely! You cannot use a spoon of “colloids” and put it in somewhere.
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How many milliliters of a 0.40%(w/v) solution of nalorphine must be injected to obtain a dose of 1.5 mg?
ozzi
The number  of Ml  of  a  0.40 %w/v solution  of   ,nalorphine  that must  be injected  to  obtain  a  dose  of 1.5 mg is  calculated as  below


since M/v%   is  mass  of solute  in  grams per 100  ml

convert Mg to  g
1 g = 1000 mg  what  about  1.5 mg =?  grams
=   1.5 /1000 = 0.0015 grams


volume is therefore =  100 (  mass/ M/v%)

= 100  x(  0.0015/ 0.4) =  0.375  ML
6 0
3 years ago
Which structures make it possible for some kinds of prokaryotic cells to move around
crimeas [40]
The correct answer of the given question above would be FLAGELLA. The structure that makes it possible for some kinds of prokaryotic cells to move around is the FLAGELLA. Prokaryotic cell is one of the types of cells. The other type is the Eukaryotic cell. This cell is found in two Kingdoms of life which are Archaea and Bacteria. Hope this answer helps.
4 0
3 years ago
Read 2 more answers
The copper(I) ion forms a chloride salt (CuCl) that has Ksp = 1.2 x 10-6. Copper(I) also forms a complex ion with Cl-:Cu+ (aq) +
Mnenie [13.5K]

Answer: (a) The solubility of CuCl in pure water is 1.1 \times 10^{-3} M.

(b) The solubility of CuCl in 0.1 M NaCl is 9.5 \times 10^{-3} M.

Explanation:

(a)  Chemical equation for the given reaction in pure water is as follows.

           CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq)

Initial:                         0            0

Change:                    +x           +x

Equilibm:                   x             x

K_{sp} = 1.2 \times 10^{-6}

And, equilibrium expression is as follows.

          K_{sp} = [Cu^{+}][Cl^{-}]

       1.2 \times 10^{-6} = x \times x

             x = 1.1 \times 10^{-3} M

Hence, the solubility of CuCl in pure water is 1.1 \times 10^{-3} M.

(b)  When NaCl is 0.1 M,

       CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq),  K_{sp} = 1.2 \times 10^{-6}

   Cu^{+}(aq) + 2Cl^{-}(aq) \rightleftharpoons CuCl_{2}(aq),  K = 8.7 \times 10^{4}

Net equation: CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)

               K' = K_{sp} \times K

                          = 0.1044

So for, CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)

Initial:                     0.1                 0

Change:                -x                   +x

Equilibm:            0.1 - x                x

Now, the equilibrium expression is as follows.

              K' = \frac{CuCl_{2}}{Cl^{-}}

         0.1044 = \frac{x}{0.1 - x}

              x = 9.5 \times 10^{-3} M

Therefore, the solubility of CuCl in 0.1 M NaCl is 9.5 \times 10^{-3} M.

7 0
3 years ago
Plllllllllllllllllllllllllllz
svlad2 [7]

Answer:

Explanation:

is insufficient to overcome intermolecular forces.

8 0
2 years ago
Read 2 more answers
How many moles are in 9.25E24 formulas units of sodium acetate?
Lelu [443]

Answer:

<h2>15.37 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{9.25 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 15.365448...

We have the final answer as

<h3>15.37 moles</h3>

Hope this helps you

5 0
3 years ago
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