Answer:
Magnitude of work done = 24.28 J
Explanation:
No. of moles = Reacting mass/ Molar mass
Reacting mass of Na = 0.45 g
Molar mass of sodium = 23g/mol
∴ No. of moles of sodium = 0.45/23 = 0.0196 mole
If 2 moles of Na react with water at 25°C and 1 atm, 24.5 L of H₂ was formed.
∴ when 0.0196 mole of Na react with water under the same conditions, (24.5×0.0196)/2 L of H₂ will be formed.
⇒ (24.5×0.0196)/2 L = 0.24 L
0.24 L × 1 atm = 0.24 L . atm
Since 1 L · atm = 101.3 J
∴ 0.24 L . atm = (0.24 L . atm ×101.3)/1 = 24.28 J
Magnitude of work done = 24.28 J
