I wrote answers in picture and I use Desmos app to solve this equations
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:


Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:


Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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Since we don't know the length of the trip, we can't find an exact answer.
However, we can write an expression for it. First, we let, T, represent the total number of miles for the trip.
Now, just divide T by 33. So our expression is T/33.
If you know the total miles of the trip, just divide it by 33 and you will have the answer.
K = -48
1. subtract 5 from both sides
-4 = k/12
2. multiply 12 from both sides to get k alone
-48 = k