Step-by-step explanation:
- <em>-x-4=</em><em>4</em><em>x</em><em>-</em><em>5</em><em>4</em>
Adding x on both sides, we get
- <em>-x-4+</em><em>x=</em><em>4</em><em>x</em><em>-</em><em>5</em><em>4</em><em>+</em><em>x</em>
- <em>-</em><em>4</em><em>=</em><em>5</em><em>x</em><em>-</em><em>5</em><em>4</em>
Adding 54 on both sides, we get
- <em>-</em><em>4</em><em>+</em><em>5</em><em>4</em><em>=</em><em>5</em><em>x</em><em>-</em><em>5</em><em>4</em><em>+</em><em>5</em><em>4</em>
- <em>5</em><em>0</em><em>=</em><em>5</em><em>x</em>
Dividing both sides by 5, we get
- <em>5</em><em>0</em><em>/</em><em>5</em><em>=</em><em>5</em><em>x</em><em>/</em><em>5</em>
- <em>1</em><em>0</em><em>=</em><em>x</em>
<em>Hence,</em><em> </em><em>the </em><em>value</em><em> of</em><em> x</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em>.</em>
Answer:
p = 0.38, n = 20
The probability that he throws more than 10 strikes = 0.09233
Step-by-step explanation:
Binomial distribution function is represented by
P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ
n = total number of sample spaces = number of times Jack wants to bowl = 20
x = Number of successes required = number of strikes he intends to get
p = probability of success = probability that Jack throws a strike = 0.38
q = probability of failure = probability that Jack doesn't throw a strike = 0.62
P(X > x) = Σ ⁿCₓ pˣ qⁿ⁻ˣ (summing from x+1 to n)
P(X > 10) = Σ ²⁰Cₓ pˣ qⁿ⁻ˣ (summing from 11 to 20)
P(X > 10) = [P(X=11) + P(X=12) + P(X=13) + P(X=14) + P(X=15) + P(X=16) + P(X=17) + P(X=18) + P(X=19) + P(X=20)
P(X > 10) = 0.09233
There are binomial distribution cacalculators that can calculate all of this at once. Get one to minimize errors.
Answer:
Step-by-step explanation:
2z-4=16
2z=20
z=10
10 mg
ANSWERS:
Between 7 & 8: √50, √62
Between 8 & 9: √70, √74
Between 9 & 10: √90, √83
Hope it helps u!
