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Ivanshal [37]
3 years ago
9

If using the method of completing the square to solve the quadratic equation

Mathematics
1 answer:
prisoha [69]3 years ago
4 0

Answer:

complete the square 2 x + 38 = 0

Step-by-step explanation:

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Which property is used 2(x+4)=2x+8
Elenna [48]

Answer:

Apply the distributive property

2x+2(4)=2x+8

Multiply 2 by 4

2x+8=2x+8

Move all terms containing x to the left and subtract 2x

2x+8-2x=8

Combine the opposite terms

2x+8-2x

Subtract 2x from 2x

0+8=8

8=8

All real number

Step-by-step explanation:

7 0
3 years ago
A high speed elevator can rise 480 feet in 30 seconds. which expression represents the rate, in feet per minute, of the elevator
AleksAgata [21]

R = 960x ft/min

Explaination : 960 is the rate at which the elevator will rise in a minute, while the 'x' represents the amount of minutes passed. Finally the label in the end clarify the units of measure.


4 0
4 years ago
HELP ME PLEASE ON THIS!!
Nata [24]

Answer:

On the ground is the answer and my chat is "devanson1".

Step-by-step explanation:

without the quotation marks

6 0
3 years ago
Help me pls its simple (hopefully)<br><br> pls dont guess
Rzqust [24]

Answer:

15.8 in.

Step-by-step explanation:

63.2 / 4 = 15.8

5 0
3 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So \mu = 375, \sigma = 68

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So n = 6, s = \frac{68}{\sqrt{6}} = 27.76

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 375}{27.76}

Z = 1.26

Z = 1.26 has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So \mu = 522, \sigma = 106

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes?

So n = 6, s = \frac{106}{\sqrt{6}} = 43.27

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 523}{43.27}

Z = -2.61

Z = -2.61 has a pvalue of 0.0045.

So there is a 1-0.0045 = 0.9955 = 99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

6 0
4 years ago
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