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cluponka [151]
2 years ago
8

Amy cut a piece of yarn 3.05 inches long for a bracelet she was making. Which length is equivalent to 3.05 inches?

Mathematics
2 answers:
Lesechka [4]2 years ago
7 0
Answer:

C. 3 1/20

Step-by-step explanation:

3.05 as a fraction = 3 1/20

Therefore the answer is C.
arsen [322]2 years ago
6 0
The answer would be c stay safe My friend I hope it’s right
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Rewrite the equation in slope-intercept form. x=4y+2
Dafna1 [17]

Answer:

y = x/4 - 1/2

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Step 1: Write equation

x = 4y + 2

Step 2: Subtract 2 on both sides

x - 2 = 4y

Step 3: Divide both sides by 4

x/4 - 1/2 = y

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3 years ago
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What diagram do I use???
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A Bar Graph

Step-by-step explanation:

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3 years ago
Any suggestions or answers <br><br> D) can’t be determined
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A

Step-by-step explanation:

3 0
3 years ago
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In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T
dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + \frac{h^{2} }{2!}f''(a) = 0

h = \frac{-f'(a) }{f''(a)} ± \frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}

So, we get the succeeding equation for Newton's method as

x_{i+1} = x_{i} + \frac{1}{f''x_{i}}  [-f'(x_{i}) ± \sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]

Part B.

It is evident that Newton's method fails in two cases, as:

1.  if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)    

Part C.

In case  x_{i+1} is close to x_{i}, the choice that shouldbe made instead of ± in part A is:

f'(x) = \sqrt{f'(x)^{2} - 2f(x)f''(x)}  ⇔ x_{i+1} = x_{i}

Part D.

As given x_{i+1} = x_{i} = h

or                 h = x_{i+1} - x_{i}

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also,             (x_{i+1}-x_{i})² = -(x_{i+1}-x_{i})(f(x_{i})/f'(x_{i}))

So,                f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes   h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also,             x_{i+1} = x_{i} -f(x_{i})/f'(x_{i}) + [(x_{i+1} - x_{i})f''(x_{i})f(x_{i})]/[2(f'(x_{i}))²]

6 0
3 years ago
Count by tens and ones to find the sum of 45+26
galben [10]
45+10= 55
55+10= 65
65+1= 66
66+1= 67
67+1= 68
68+1= 69
69+1= 70
70+1= 71

Because 10+10+1+1+1+1+1+1= 26,
71 is your answer :)
4 0
3 years ago
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