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stepan [7]
3 years ago
13

What is the equation of a line perpendicular to y=¼x-3 that passes through point (-2,4)​

Mathematics
2 answers:
yawa3891 [41]3 years ago
7 0

Answer:

<h2>y = -4x - 4</h2>

Step-by-step explanation:

adoni [48]3 years ago
5 0
In order for a line to be perpendicular, its slope must be the negative reciprocal of the other line. We’re solving for the b part of y = mx + b

The new line = -4x + b

4 = -4(-2) + b

4 = 8 + b

b = -4

The equation of the line is y = -4x - 4
You might be interested in
A bird feeder 24 times using 6 cups each time. A bag of seeds holds 32 cups. How many bags of seed did he use?
pishuonlain [190]

First, let's find how many cups the bird feeder uses 24 times.

24 x 6 = (20 x 6) + (4 x 6) = 120 + 24 = 148 cups.

Now, let's divide 148 by 32.

148 ÷ 32 = 4.625 bags of seed.

I hope this helped!

6 0
2 years ago
Find a and b. А E b B 409 с D​
babymother [125]

Answer:

a = 70°, b = 140°

Step-by-step explanation:

use alternate interior angles

The interior angles of a straight line are 180°

a = 180°-110° = 70°

b = 180°-40° = 140°

//I'm sorry, but I'm not very fluent in English.

7 0
2 years ago
If f(x)=4x^2 and g(x)=x+1, find (fog)(x)
iren [92.7K]

Answer: The value of (f_\circ g)(x)  is  4(x+1)^2  .

Step-by-step explanation:

Given: f(x) = 4x^2 \text { and } g(x) = x+1

To find: (f_\circ g)(x)

As we know it is composition function which means that  g(x) function is in f(x) function.

So we have

(f_\circ g) (x) =  f[g(x)]

\Rightarrow( f_\circ g)(x)= f(g(x)) = 4(g(x))^2

Now substitute the value of g(x) we get

(f_\circ g)(x)= 4(x+1)^2

Hence, the value of (f_\circ g)(x)  is  4(x+1)^2  .

5 0
3 years ago
Need some help please!!​
ella [17]

Answer:

The other point on the diameter which is also on the circle is; (-3, 2)

Step-by-step explanation:

The center of the circle, also a point where the diameter crosses, is (3, 6)

The diameter touches the circle at point (9, 10)

The displacement is (9 - 3, 10 - 6) = (6, 4)

This means that we move, +6 units along the x-axis and +4 units along the y-axis , from the center of the circle in order to reach point (9, 10)

If we want to reach the other point on the diameter which also on the circle, we move -6 units along the x-axis and -4 units along the y-axis to get;

(3, 6) - (6, 4) = (-3, 2)

6 0
3 years ago
7. Write the equation of a line which passes through the points (-3,5) and (6,23)
faust18 [17]

Answer:

answer to the equation is

y = 2x + 11

Step-by-step explanation:

y = mx + b

first find the slope of the line using the two points

slope \: m =  \frac{y2 - y1}{x2 - x1}  =  \frac{23 - 5}{6 - ( - 3)}   \\ =  \frac{18}{9}  \\ slope \: m = 2

substitute 2 for m and use one of the points for x and y and solve for b

5 = 2( - 3) + b \\ 5 =  - 6 + b \\ 5 + 6 = b \\ b = 11

Now that you found b, the y-intercept, you can substitute that into the equation for your line

y = 2x + 11

7 0
2 years ago
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