Answer:
2
Step-by-step explanation:
see the image for the explanation
Answer:

Step-by-step explanation:
We want to model the position of the submarine as a function of time.
Notice that we have a constant amount. The initial depth: 750 meters
Then we have a factor that varies over time. Every hour the submarine ascends 50 meters. therefore as t increases the depth y(t) of the submarine decreases. Then the factor is:
-50t.
Where t represents the time in hours.
Then the equation that represents the new position of the submarine in relation to the level of the sea:

Hello :
(-6a)-(-3a) =(-3a)-(0) = (0)-(3a) = (3a)-(6a) = -3a (arthmetic<span> sequence, the common - diff is : d= -3a the first term is : U1 = 6a
</span><span>a general rule for the n th term is : Un =U1+(n-1)d
Un = 6a +(n-1)(-3a) =
Un = 6a -3an+3a
</span>Un = -3an +9a
Area = πr²
50 = πr²
r = √50/π
so diameter = 2√50/π
which is = 7.98m to 3sf
Age of Jen is 13.6 years old
<em><u>Solution:</u></em>
Let "x" be the age of Jack and "y" be the age of Jen
Given that This Christmas, your brother Jack will be 2 years from being twice as old as your sister Jen
The above sentence can be written mathematically as:
Jack age + 2 = twice of age of Jen

The sum of Jacks age and three times Jen's age is 66
Jack age + three times Jen age = 66
x + 3y = 66 ---- eqn 2
Substitute eqn 1 in eqn 2
2y - 2 + 3y = 66
5y - 2 = 66
5y = 68
<h3>y = 13.6</h3>
Thus age of Jen is 13.6 years old