When we are given a function f(x) and we are asked for f(a) [a is any number], it means to replace (or substitute) a into x in the function (x=a)
In this problem, we are asked to replace x with 2 in f(x), the first equation, and replace x with 3 in the second equation.
It looks like this:
f(2) = 2^3 + 5(2)^2 = 8 + 5(4) = 8 + 20 = 28
g(3) = 2(3) + 4 = 6 + 4 = 10
We finally just add these two numbers from f(2) and g(3) and get 28 + 10 = 38
Remark
Let f(x) = y must to make it easier to write.
Equation
Original Equation: y = (x - 5)/3
Inverse
Interchange the x and y. You get x = (y - 5) / 3
Solve for y in the inverse.
x = (y - 5)/3 Multiply by 3
3x = y - 5 Add 5 to both sides.
3x + 5 = y
<u><em>substitute f1(x) back into the equation.</em></u>
3x + 5 = f(x) Now put in 3 for x
f(3) = 3x + 5
f(3) = 3*3 + 5
f(3) = 14 <<< Answer
Answer:QB = 1/2 QE
QC = CF
DE = 2AB
Step-by-step explanation: hope it works
Answer:
or 
Step-by-step explanation:
<u>Step 1: Cross Multiply</u>
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<u>Step 2: Divide both sides by 2.35</u>
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or
Answer: or
Answer:
25%
Step-by-step explanation:
Say we start from the beginning with $40. If the pants are discounted but we don't know the percent discount, then we need a variable, x:
40 - x% * 40 = 30
The total is 40. When we take a discount off of 40, we are taking a percent of 40 and subtracting that from 40. From the problem, this should be 30. Thus, the equation above.
Add x%*40 to both sides and subtract 30 from both sides:
x%*40 = 10
Divide by 40:
x% = 1/4 = 0.25
Multiply each side by 100:
x = 25
The answer is 25%.
