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ASHA 777 [7]
3 years ago
8

a species of rodent can either have brown fur or white fur. Brown fur is recessive and white fur is dominant. what would cause t

he rodent population to not be in Hardy-Weinberg Equlibrium
Biology
2 answers:
Shalnov [3]3 years ago
8 0

The mutation as the Hardy- Weinberg equation assumes that there would be no evolutionary pressures such as mutations. Hardy- Weinberg represents an 'ideal' where the allele frequencies would remain constant

The rodents mutate the new grey allele.
Elden [556K]3 years ago
3 0

Answer:

There must be no genetic flow, mutation, random mating or gene duplication/deletion and natural selection with in the species of rodents to maintain Hardy-Weinberg Equlibrium

Explanation:

A hardy Weinberg equilibrium has certain exemptions which if not restricted would lead to a non hardy Weinberg equilibrium.

These assumptions are as follows -

a) There should be no mutation in allele genes

b) Genes must not be duplicated or deleted

c) There should be no random mating between organism

d) There should be no gene flow  

e) All alleles must be of equal fitness and hence there must be no natural selection.

Thus, there must be no genetic flow, mutation, random mating or gene duplication/deletion and natural selection with in the species of rodents having brown or white fur to maintain Hardy-Weinberg Equlibrium

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4 0
3 years ago
Assignment: Using Punnett Squares Exploration
amm1812

Answer:

Explanation:

Genotype 1:

2/4 is RR so RR is 50%

2/4 is Rr so Rr is 50%

Phenotype:

Not enough info for that

Genotype 2:

1/4 is RR so RR is 25%

2/4 is Rr so Rr is 50%

1/4 is rr so rr is 25%

Phenotype:

?

Genotype 3:

4/4 is rr so rr is 100%

Phenotype:

??

3 0
3 years ago
Read 2 more answers
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