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2 years ago

Which postulate or theorem can be used to prove that AABC = ADCB? SSS ASA SAS AAS

Mathematics

1 answer:

koban [17]2 years ago

6 0

<h3>Answer : </h3>

SSS congruency criteria can be used here to prove ∆ABC ≅ ∆DCB

<h3>Solution : </h3>

In ∆ABC and ∆DCB

AB = CD (given)

AC = BD (given)

BC = BC (common)

So, by SSS congruency criteria,

∆ABC ≅ ∆DCB

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The values of the 2s in 2,201,538 are.

Ronch [10]

Answer:

First Two: 2 million,

Second Two: 2 hundred thousand

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3 years ago

Evaluate 14+ (- 2)<br> A) 12<br> B)- 12<br> C) 16<br> D)- 16

11111nata11111 [884]

The answer would be A.12

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2 years ago

Solve the inequality<br> 4b−4≤−20

devlian [24]

Answer:

b ≤ -4

Step-by-step explanation:

4b−4≤−20

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2 years ago

Choose the correct simplification of 8x2(4x 2x2 − 1). (5 points) group of answer choices 32x4 − 16x3 8x2 32x4 16x3 − 8x2 16x4 −

nekit [7.7K]

The second option is the correct answer

$16x^{4}+40x^{3} -24x^{2}$

The expression given to us is:

$8x^{2} (5x+2x^{2}-3 )$

Herein, we can simplify it by opening up the bracket and multiplying each term inside the bracket by the term which is outside the bracket.

Thus, we get:

$8x^{2} (5x+2x^{2}-3 )=8*5x^{2+1} +8*2x^{2+2}-8*3x^{2}$

$40x^{3} +16x^{4}-24x^{2}$

Rearranging the above expression in descending order of power we get:

$16x^{4}+40x^{3} -24x^{2}$

From the given options we can see this is the second option. Hence the second option is the correct answer.

Learn more about equation here brainly.com/question/14180340

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1 year ago

(f) how many ways are there to place a total of m indistinguishable balls into n distinguishable urns, with some urns possibly e

Blizzard [7]

The number of different ways to distribute m indistinguishable balls into n distinguishable urns is given by C(m+n-1,n-1).

For example, the number of ways 6 ball can be placed in 7 boxes is given by C(6+7-1, 7-1) = C(12, 6) = 924 ways.

4 0

2 years ago