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Amiraneli [1.4K]
2 years ago
9

Is x=12 a solution to the given inequality x > 5

Mathematics
1 answer:
Ludmilka [50]2 years ago
4 0

Answer: True

Step-by-step explanation:

Substitute 12 for x in the inequality

x > 5

12 > 5

12 is greater than 5 so x = 12 is a solution to x > 5

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Please math , help
Furkat [3]

Answer:

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

Step-by-step explanation:

Mean of the batch:

The mean of the batch is the sum of all values divided by the number of items. So

M = \frac{199+204+201+197+195+204+200}{7} = 200

Mean in the desired interval.

Standard deviation:

Square root of the sum of the difference squared between each term and the mean, divided by the number of items. So

S = \sqrt{\frac{(199-200)^2+(204-200)^2+(201-200)^2+(197-200)^2+(195-200)^2+(204-200)^2+(200-200)^2}{7}} = 1.18

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

7 0
3 years ago
There are 5 different pairs of gloves, where left and right are distinguishable. Select 4 of the 10 gloves. (a) How many are the
Shtirlitz [24]

Answer:

(a) How many are there to select 2 pairs of gloves?

10 ways

(b) How many ways are there to select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.)

130 ways

Step-by-step explanation:

We solve the above questions using Combination

Combination = C(n, r) = nCr

= n!/n! ×(n - r)!

(a) How many are there to select 2 pairs of gloves?

We have 5 pairs of gloves. Therefore, the number of ways to select 2 gloves =5C2

= 5!/2! × (5 - 2)!

= 5!/2! × 3!

= 5 × 4 × 3 × 2 × 1/(2 × 1) × (3 × 2 × 1)!

= 10 ways.

(b) How many ways are there to select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.)

We are told to select 4 gloves out of the 10 gloves = 10C4

We have 5 pairs, we need to make sure that two out of the selected 4 make a pair = 5 × 2⁴

= 80

Hence,

10C4 - 5C4

= [10!/4! × (10 - 4)!] - 80

= 210 - 80

= 130 ways

3 0
3 years ago
James can jog twice as fast as he can walk. He was able to jog the first 9 miles to his grandmother’s house, but then he tired a
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Let the speed of walking of James = x mile/hour

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or, (9 + 3)/2x = 2

or, 12 = 4x

or, x = 3

Average speed of walking = 3 mile/hour

Average speed of jogging = 2 * 3 = 6 mile/hour

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