Answer: b. Side BC and Side KL
Step-by-step explanation:
Only these two lines are in the same positions.
<h3>What is the domain of the relation</h3>
R = {(-2, 4), (1, 3), (0, -4), (3, 2)}?
- A. (-2, 0, 1, 3}
- C. {0, 1, 2,4}
- B.{-4, -2, 2, 3}
- D. {-4,2,3,4}
<h2>Answer:-</h2>
Domain of relation is (-2, 1,0,3}
so option 1st is correct
<h2>________________</h2>
Answer:
The total cost would be: $62.14
Step-by-step explanation:
First convert the percent to a decimal, so since it is 4%, you move the decimal two places to the right, so it would be .04.
Next, multiply $59.75 x .04%. This equals $2.39.
Then, take the product and add it to $59.75. So, $59.75 + $2.39.
This equals $62.14!
Step-by-step explanation:
Alright so, we need need to lay down the clues we were given
●Ratio of the seats= 2:5
● No.of seats in the circle
●Fraction of seats occupied for the stalls
Now, let us take a closer look at the ratio;
<em>C</em><em>:</em><em> </em><em>S</em><em> </em><em> </em><em>Total</em>
2:5 7
As we can see, the number of parts for the circle is 2 parts.
So ,
2 parts = 528 seats
1 part= 528/2= 264 seats
5 parts= 1 320 seats
7 parts= 264 × 7 = 1 848
Finally,
We can now find the seats occupied by the stalls,
2/3 × 1 320
= 880 seats
Seats of circle + Seats of stall
= 528 + 880= 1408
Percentage Occupancy
=
1408/1 848 × 100
Note: The answer will come in decimal numbers.
It will be,
76.1904761905
or
76.19%
ANSWER
Yes there is actually a formula for this. This is an arithmetic progression with a common difference of 1.
The sum of terms can be solved by using the formula
S = (n/2) * (a1 + an)
where S is the sum of the terms
n is the number of terms
a1 is the first term
an is the last term
we can calculate the number of terms, n by using the formula
an = a1 + (n-1)*d
d is the common difference equal to 1
therefore n = 51
substituting to the first equation
S = 2805
