Choosing 4 men from seven can be done in 7C4 = 35 ways
(There are 7 to choose from then 6 and 5 and 4 = 7 x 6 x 5 x 4
but we don’t want them in order so we need to divide by 4! = 4 x 3 x 2 x 1)
Similarly choosing 4 women from 11 can be done in 11C4 = 330 ways.
Total number of ways to choose 4 men and 4 women = 35 x 330 = 11550
Answer:
Step-by-step explanation:
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Answer:
that is the answer
Step-by-step explanation:
Answer:
(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Step-by-step explanation:
Using the identity for the difference of 2 squares;
a^2 - b^2 = (a - b)(a + b)
we put a^2 = 81x^8 and b^2 = 1 giving
a = 9x^4 and b = 1, so:
81x^8 − 1 = (9x^4 - 1)(9x^4 + 1)
Applying the difference of 2 squares to 9x^4 - 1:
= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).
Answer:
Small no. is 15
Larger no. is 15 + 27 = 42
Step-by-step explanation:
Let the small no. be x
Larger no. will be x + 27
5x + x + 27 = 117
6x + 27 = 117
6x = 117-27
x = 90/6
x = 15
