<span>(8,9) m = 0.5
point slope form
y - y1 = m (x - x1)
so
equation
y - 9 = 0.5(x - 8)
answer
</span>
y - 9 = 0.5(x - 8)
Answer:
37 mph
Step-by-step explanation:
Sum of forces on the car in the y direction:
∑F = ma
N − mg = 0
N = mg
Sum of forces on the car in the x direction:
∑F = ma
-Nμ = ma
-mgμ = ma
-gμ = a
Given μ = 0.75 and g = 32 ft/s²:
a = -(32 ft/s²) (0.75)
a = -24 ft/s²
Use kinematics to find the initial velocity.
v² = v₀² + 2aΔx
(0 ft/s)² = v₀² + 2 (-24 ft/s²) (60 ft)
v₀ ≈ 53.7 ft/s
v₀ ≈ 37 mph
Check the picture below.
something worth noticing 
so, we're really graphing x+2, with a hole at x = 3, however, when x = 3, we know that f(x) = 5, but but but, when x = 3, x+2 = 5, so we end up with a continuous line all the way, x ∈ ℝ, because the "hole" from the first subfunction, gets closed off by the second subfunction in the piece-wise.
Answer:

Step-by-step explanation:
Use FOIL: <em>(a + b)(c + d) = ac + ad + bc + bd</em>
