Let's assume
people were in the original group of winners as x
A group of winning ticket holders share equally 90,000,000 lottery
Before the money is divided, three more winning ticket holders are declared
so, total number of winning tickes =x+3
each persons share is reduced to 5,000,000
so, total money =5,000,000*(x+3)
and this must be equal to total money

now, we can solve for x
and we get

Subtrac both sides by 3


so,
number of people were in the original group of winners is 15 ...........Answer
F^-1(x)= x/9 + 1/3
To find this, just interchange the variables and solve for y.
y=9x-3
x=9y-3
x+3=9y
divide by nine
Step-by-step explanation:m okay so the answer is 56 x= 56
P(x) = x^2 - 1
q(x) = 5(x - 1)
(p - q)(x) = p(x) - q(x) = (x^2 - 1) - 5(x - 1)