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Shkiper50 [21]
2 years ago
11

PLEASE HELP AND FAST

Mathematics
1 answer:
marissa [1.9K]2 years ago
5 0
When reflecting over the x-axis, the y value change.

When reflecting over the y-axis, the x value change.
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10=z+6<br>Plz help me with this
garik1379 [7]

Answer:

z=4

Step-by-step explanation:

6+4=10

6 0
3 years ago
What is the equation of the graph in slope-intercept form?
Slav-nsk [51]
The answer is B y=4x-6
7 0
2 years ago
Solve the equation. 2x+1/3+x-1/4=13/2
inessss [21]

The solution of the equation is x = 71 / 36.

<h3>How to solve an equation with one variable</h3>

Herein we have an equation with several rational constants and only one variable, x, which has to be cleared by using algebra procedures. The procedure is shown below:

2 · x + 1 / 3 + x - 1 / 4 = 13 / 2           Given

2 · x + x = 13 / 2 - 1 / 3 - 1 / 4            Compatibility with addition / Existence of additive inverse / Modulative property

3 · x = 71 / 12                                    Definitions of addition and subtraction / Distributive property

x = 71 / 36                                         Compatibility with multiplication / Existence of multiplicative inverse / Modulative property / Result

The solution of the equation is x = 71 / 36.

To learn more on equations: brainly.com/question/10413253

#SPJ1

4 0
1 year ago
An angle, θ, is in standard position. The terminal side of the angle passes through the point (4, 5).
lara31 [8.8K]

Answer:

cos Θ = \frac{4}{\sqrt{41} }

Step-by-step explanation:

Given the angle passes through (4, 5 ) then the right triangle with sides 4 and 5 has hypotenuse h given by

h² = 4² + 5² = 16 + 25 = 41 ( take the square root of both sides )

h = \sqrt{41}

In relation to Θ, 4 is adjacent and 5 is opposite, thus

cos Θ = \frac{adjacent}{hypotenuse} = \frac{4}{\sqrt{41} }

5 0
3 years ago
What's the area of this triangle
Luda [366]

Answer:

D      A = (1/2) (y₂ - y₁)(x₃ - x₁)

Step-by-step explanation:

b = (y₂ - y₁)

h = (x₃ - x₁)

A = (1/2)bh

A = (1/2) (y₂ - y₁)(x₃ - x₁)

8 0
2 years ago
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