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Naily [24]
3 years ago
13

Rationalising factor of 5 +root 7

Mathematics
2 answers:
Phantasy [73]3 years ago
7 0

Answer:

Therefore, lowest rationalizing factor is ( 7 + √7 ).

Step-by-step explanation:

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DIA [1.3K]3 years ago
3 0

Answer:

5 - \sqrt{7}

Step-by-step explanation:

To rationalise the factor multiply by the conjugate factor

The conjugate of 5 + \sqrt{7} is 5 - \sqrt{7} , then

(5 + \sqrt{7} )(5 - \sqrt{7} ) ← expand using FOIL

= 5² - (\sqrt{7} )²

= 25 - 7

= 18

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4 years ago
The length of a rectangle is 2 units more than the width. The area of the rectangle is 63 units. What is the length, in units, o
Keith_Richards [23]

Answer:

Length = 9units

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Step-by-step explanation:

It is said that the length is 2units more than the width

Assume that the width is x, then the length will be 2 + x

ie

Width = x

Length = 2 + x

Area of the rectangle = 63units

Area of rectangle = l * b

l - length of the rectangle

b - width of the rectangle

A = l * b

63 = (2 + x) * x

63 = ( 2 + x) x

63 = 2x + x^2

Let's rearrange it

x^2 + 2x - 63 = 0

Let's find the factor of 63

A factor that can be multiplied to give -63 and that can be added to give +2

Let's use -7 and +9

x^2 - 7x + 9x - 63 = 0

Separate with brackets

( x^2 - 7x) + ( 9x - 63) = 0

x( x - 7) + 9(x - 7) = 0

( x + 9)(x - 7) = 0

( x + 9) = 0

( x - 7) = 0

x + 9 = 0

x = -9

x - 7 = 0

x = 7

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So therefore,

x = 7

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3 years ago
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masya89 [10]

Answer:−10x-12

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3 years ago
Read 2 more answers
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