Lines s, t, and u are perpendicular bisectors of the sides of FGH and meet at J. If JG = 3x + 4, JH = 2y - 2, JF = 10 and HI = 2

Question

Lana71 [14]

2 years ago

8

Lines s, t, and u are perpendicular bisectors of the sides of FGH and meet at J. If JG = 3x + 4, JH = 2y - 2, JF = 10 and HI = 2

z - 4, find x, y, and z.

Mathematics

1 answer:

Rainbow [258] · Answer 1 · 2022-02-24T19:45:55+03:00

Answer:

x = 4, y = 6, z = 8

Step-by-step explanation:

Given that for a triangle FGH, lines s, t and u are perpendicular bisectors.

They concur at the point J.

We know that the point of concurrence of perpendicular bisectors is the circmcenttre of the triangle. Hence we will have J equidistant from the three vertices. In other words,

JG = JH=JF

Now to find Z we make use of HI.

So 8 is right answer

x = 4, y = 6, z = 8

Step-by-step explanation:

sorry i took to long