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2 years ago

Explain how to use the Pythagorean Theorem to find the missing length of a right triangle.

Mathematics

1 answer:

tino4ka555 [31]2 years ago

6 0

Pythagorean theorem.

a^2+b^2=c^2

This means that the square of the length of the 2 legs of a right triangle added together = the square of the length of the hypotenuses or diagonal.

If you know 2 of the values in the 3 variables a,b,c what would you do to find the missing variable value?

I will not write the exact answers to this problem. I think you can figure how to write it out yourselves.

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Lee sells electronics. He earns a 5% commission on each sale he makes.

NISA [10]

Answer:

a) c = (5/100)*d

b) c = 0.05*d

c) The ratio between what Lee recieves and what he sold.

d) d = 2000

Step-by-step explanation:

Since Lee earns 5% in commission for each sale then:

a) c = (5/100)*d

b) c = 0.05*d

c) In this context the constant of proportionality means the ratio of the value Lee sold that he'll earn as a comission.

d) Since he wants to earn $100, then c = 100 and we solve for d

c = 0.05*d

100 = 0.05*d

0.05*d = 100

d = 100/0.05 = $2000

He needs to sell $2000.

3 0

3 years ago

Please help me .. Use the distributive property to factor the expression. 2k + 10

Aleksandr [31]

Answer:

2×(1+10)

Step-by-Step

You are just substituting in where the parenthesis go.

But I am not entirely sure.

5 0

3 years ago

Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi

Leona [35]

Answer:

The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Step-by-step explanation:

Explanation:-

Given equation is

$2cosx-\sqrt{3} =0 for 0$

$2cosx =\sqrt{3}$

Dividing '2' on both sides, we get

$cos x =\frac{\sqrt{3} }{2}$

$cos x = cos(\frac{\pi }{6})$

General solution of cos θ = cos ∝ is θ = 2nπ±∝

Now The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

put n=0

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Put n=1

$x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}$

$x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}$

put n=2

$x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}$

$x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}$

And so on

But given 0 < x< 2π

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

6 0

3 years ago

Simplify and solve each equation for the x

Olegator [25]

Answer:

19y - 7y = 1 + 4(x+2x)

y = 1/12 + x

x = y - 1/12

I hope this helps!

8 0

2 years ago

What is 8/16 I will give brainlyist

zepelin [54]

Answer:one half

Step-by-step explanation:

3 0

3 years ago

Explain how to use the Pythagorean Theorem to find the missing length of a right triangle.​

Explain how to use the Pythagorean Theorem to find the missing length of a right triangle.