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kupik [55]
3 years ago
15

Please help me answer this ​

Mathematics
1 answer:
jonny [76]3 years ago
4 0
The answer is 112 im pretty sure!
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Find the missing side of each triangle. 8 km and 16 km
geniusboy [140]

Answer:

c

i hope this work for you

and sory if im wrang

4 0
2 years ago
Mandisa draws a rectangle to represent the area of her yard. The area can be represented by 10x2 – 13x – 14.What expressions can
Y_Kistochka [10]

Answer: (x–2) and (10x+7)

Step-by-step explanation:

10x^2 – 13x – 14=

10x^2 – 20x + 7x – 14=

10x(x–2) + 7(x–2)=(x–2)(10x+7) ==> 3rd option

4 0
2 years ago
Please help! this is due today and this is the only question left!!
Soloha48 [4]

Answer:

13.73 sq mm

Step-by-step explanation:

Area of Square - Area of Circle = Area of Shaded Region

if radius of circle is 4 then diameter is 8

the diameter is the same as the length of each side of the square

so area of square = 8² or 64

Area of Circle = 16π

64 - 16π ≈ 13.73

7 0
3 years ago
Find an equation of the line passing through each of the following pairs of points. a (−3, 1), (0, 3)
Svetlanka [38]

\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-3)}}}\implies \cfrac{2}{0+3}\implies \cfrac{2}{3}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{2}{3}}[x-\stackrel{x_1}{(-3)}]\implies y-1=\cfrac{2}{3}(x+3) \\\\\\ y-1=\cfrac{2}{3}x+2\implies y=\cfrac{2}{3}x+3

5 0
3 years ago
Please any one help me ​
Ulleksa [173]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Since it's a Trapezoid with its non - parallel sides equal to one another,

\qquad \sf  \dashrightarrow \:\angle A + \angle P = 180

[ By forming co - interior angle pair ]

\qquad \sf  \dashrightarrow \:\angle A +100 = 180

\qquad \sf  \dashrightarrow \:\angle A = 180 - 100

\qquad \sf  \dashrightarrow \:\angle A = 80

Now, similarly,

\qquad \sf  \dashrightarrow \:\angle A + \angle R = 180

\qquad \sf  \dashrightarrow \: \angle R + 80 = 180

\qquad \sf  \dashrightarrow \: \angle R  = 100

Similarly,

\qquad \sf  \dashrightarrow \angle K + \angle R = 180

\qquad \sf  \dashrightarrow \angle K + 100 = 180

\qquad \sf  \dashrightarrow \angle K  = 80

3 0
2 years ago
Read 2 more answers
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