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3 years ago

Mea 2, 7, 7, 2, 2, 4 Mean Median

Mathematics

2 answers:

frozen [14]3 years ago

8 0

2+7+7+2+2+4 divide by 6 = mean
7 times 2 divided by 2=median

Pepsi [2]3 years ago

4 0

Mean: 4
Median: 3
That’s the answer

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Find the area of the shaded region. Round the nearest hundredth if necessary. YZ=14.2m

andreyandreev [35.5K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$A_1 = 67.58 \ in^2$

$A_2 =415.4 \ ft^2$

$A_3 = 8.48 \ cm^2$

$A_4 = 480.38 \ m^2$

Step-by-step explanation:

Generally the area of a sector is mathematically represented as

$A = \frac{\theta}{360} * \pi r^2$

Now at $r_1 = 11 in$ and $\theta_1 = 64^o$

$A_1 = \frac{64}{360} * 3.142 * 11^2$

$A_1 = 67.58 \ in^2$

Now at $r_2 = 20 ft$ in and $\theta_2 = 119 ^o$

$A_2 = \frac{119}{360} * 3.142 * 20^2$

$A_2 =415.4 \ ft^2$

Now at $r_3 = 6.5 cm$ and $\theta_3 = 23 ^o$

$A_3 = \frac{23}{360} * 3.142 * 6.5 ^2$

$A_3 = 8.48 \ cm^2$

Now at $r_4 = 14.2 m$ and $\theta_4 = 360 -87 = 273 ^o$

$A_4 = \frac{273}{360} * 3.142 * 14.2^2$

$A_4 = 480.38 \ m^2$

6 0

3 years ago

Please someone help me‼️

Flauer [41]

Answer:

6 m

Step-by-step explanation:

The volume of a cone is found by $\frac{\pi r^2h}{3}$ , so we can plug the values in to get 6pi * r^2 / 3 = 72pi, or 6pi * r^2 = 216 pi, so r^2 = 36 and the radius is 6 m.

4 0

3 years ago

One bushel of apples weighs 22<br> kilograms. How many kilograms<br> do 5.7 bushels weigh?

Solnce55 [7]

Answer:

125.4 kg

Step-by-step explanation:

I attached a picture of my work and I stuck it into my calculator to check it

5 0

3 years ago

The angles shown are supplementary. What is the value of x ?

almond37 [142]

Answer:

Step-by-step explanation:

This is because if u subsitute x with 17, 17x5 is 85 and 85+95= 180

5 0

2 years ago

Read 2 more answers

A television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If

Alinara [238K]

Answer:

Test statistic z= 1.708

Step-by-step explanation:

given that a television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If this is to happen, it will have to move one of its most viewed shows to another slot.

Sample size n = 827

Sample proportion p = $\frac{438}{827} \\=0.5297$

$H_0: p =0.5\\H_a: p >0.5$

(right tailed test)

This is because they would be interested if more than half viewers are ready for the change

Test statistic = Z = p difference/std error

p difference = 0.0297

Std error = $\sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.5*0.5}{827} } \\=0.0174$

Z =1.708

p valu e= 0.9562

Since p >0.05 we fail to reject H0

Test statistic z= 1.708

8 0

3 years ago