Use Fnet*t=p
Fnet=mv2-mv1÷t
Fnet=3(12)-3(0)÷1.5
Fnet=36÷1.5
Punch this intoba calculator and get your answer. S.I unit = N
Answer:
5.43 x 10^-3 Nm
Explanation:
N = 52.5, radius, r = 5.35 cm = 0.0535 m, B = 0.455 T, I = 25.3 mA = 0.0253 A
Torque = N I A B Sin theta
Here, theta = 90 degree
Torque = 52.5 x 0.0253 x 3.14 x 0.0535 x 0.0535 x 0.455
Torque = 5.43 x 10^-3 Nm
Answer:
0.345m
Explanation:
Let x (m) be the length that the spring is compress. If we take the point where the spring is compressed as a reference point, then the distance from that point to point where the ball is held is x + 1.1 m.
And so the potential energy of the object at the held point is:
where m = 1.3 kg is the object mass, g = 10m/s2 is the gravitational acceleration and h = x + 1.1 m is the height of the object with respect to the reference point
According to the conservation law of energy, this potential energy is converted to spring elastic energy once it's compressed
where k = 315 is the spring constant and x is the compressed length
x = 0.345 m or x = -0.263 m
Since x can only be positive we will pick the 0.345m
The sum of all forces=m(mass) times a(acceleration). F=5.5(kg)*4.2(m/s^2)= 23.1N or D.
Fist one is a cylinder
the second, i believe is a sphere
the third is a rectangular prism
and the last is the same as the first, a cylinder