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3 years ago

What is the value of x? Enter your answer in the box. x =

Mathematics

2 answers:

dangina [55]3 years ago

7 0

Answer: The answer is 8. Hope that helps.

Step-by-step explanation:

myrzilka [38]3 years ago

6 0

Hello,

To solve this problem, you can use the Pythagorean Theorem.

It is: a² + b² = c²

If you input the 6 for a and the 10 for c, you get:

6² + b² = 10²

Now, you just have to solve the equation.
36 + b² = 100
b² = 64
b = 8

The missing side is 8.

Good luck,
MrEQ

You might be interested in

Solve 3[-x + (2 x + 1)2 = x - 1<br><br><br> X=?

Anna007 [38]

Answer:

x=−7/8

Step-by-step explanation:

3 0

3 years ago

What is the answer for this?

pantera1 [17]

Answer:

The general formula for nth term of given sequence is:

$G_n = 54 . (\frac{1}{3})^{n-1}$

Step-by-step explanation:

Given sequence is:

54,18,6.....

In order to write the general formula of a sequence, first of all the common ratio has to be found. Common ratio is the ratio between consecutive terms of a geometric sequence.

$Here\\a_1 = 54\\a_2 = 18\\a_3 = 6\\And\\r = \frac{a_2}{a_1} = \frac{18}{54} = \frac{1}{3} \\r = \frac{a_3}{a_2} = \frac{6}{18} = \frac{1}{3}$

The general formula is:

$G_n = A_1 (r)^{n-1}$

Putting the values of a1 and r

$G_n = 54 . (\frac{1}{3})^{n-1}$

Hence,

The general formula for nth term of given sequence is:

$G_n = 54 . (\frac{1}{3})^{n-1}$

4 0

3 years ago

Which equation(s)

aleksandrvk [35]

Answer:

C) y = 12 x Represents the proportional relationship.

Step-by-step explanation:

Two quantities P and Q are said to be proportional if and only if:

$P \propto Q \implies P = k Y$

Here: K = Proportionality Constant

Now, here the given expression are:

$1. y = 7 x^2\\\implies y \neq kx$

So, y is NOT PROPORTIONAL to x.

$2. y = 2 + 3x\\\implies y \neq kx$

So, y is NOT PROPORTIONAL to x.

$3. y = 12 x\\\implies y = kx, k = 12$

So, y is PROPORTIONAL to x.

$2. y = 5 - x\\\implies y \neq kx$

So, y is NOT PROPORTIONAL to x.

5 0

3 years ago

Help me with these please

olchik [2.2K]

Step-by-step explanation:

(1) y = x e^(x²)

Take derivative with respect to x:

dy/dx = x (e^(x²) 2x) + e^(x²)

dy/dx = 2x² e^(x²) + e^(x²)

dy/dx = (2x² + 1) e^(x²)

Take derivative with respect to x again:

d²y/dx² = (2x² + 1) (e^(x²) 2x) + (4x) e^(x²)

d²y/dx² = (4x³ + 2x) e^(x²) + 4x e^(x²)

d²y/dx² = (4x³ + 6x) e^(x²)

Substitute:

d²y/dx² − 2x dy/dx − 4y

= (4x³ + 6x) e^(x²) − 2x (2x² + 1) e^(x²) − 4x e^(x²)

= 4x³ + 6x − 2x (2x² + 1) − 4x

= 4x³ + 6x − 4x³ − 2x − 4x

= 0

(2) y = sin⁻¹(√x)

sin y = √x

sin²y = x

Take derivative with respect to x:

2 sin y cos y dy/dx = 1

sin(2y) dy/dx = 1

dy/dx = csc(2y)

Take derivative with respect to x again:

d²y/dx² = -csc(2y) cot(2y) 2 dy/dx

d²y/dx² = -2 csc²(2y) cot(2y)

Substitute:

2x (1 − x) d²y/dx² + (1 − 2x) dy/dx

= 2 sin²y (1 − sin²y) (-2 csc²(2y) cot(2y)) + (1 − 2 sin²y) csc(2y)

Use power reduction formula:

= (1 − cos(2y)) (1 − ½ (1 − cos(2y))) (-2 csc²(2y) cot(2y)) + (1 − (1 − cos(2y))) csc(2y)

= (1 − cos(2y)) (1 − ½ + ½ cos(2y)) (-2 csc²(2y) cot(2y)) + cos(2y) csc(2y)

= (1 − cos(2y)) (½ + ½ cos(2y)) (-2 csc²(2y) cot(2y)) + cot(2y)

= (cos(2y) − 1) (1 + cos(2y)) csc²(2y) cot(2y) + cot(2y)

= (cos²(2y) − 1) csc²(2y) cot(2y) + cot(2y)

= -sin²(2y) csc²(2y) cot(2y) + cot(2y)

= -cot(2y) + cot(2y)

= 0

8 0

3 years ago

The function f(x)=x^3+6x^2+8x

dem82 [27]

The function increases in the interval (-∞, -3) and the function also increases in the interval (-1,∞) .

The given function is of the form

f(x) = x³ + 6x² + 8x

Now we take the first differentiation of the function

f'(x) = 2x² + 12x + 8

f'(x) = 2 (x² + 6x + 9) -10

f'(x) = 2(x+3)² - 10

Therefore at x = -3 , f'(x) = -10.

Hence the function is increasing in the interval of (-∞, -3)

Again f'(x) = 2x² + 12x + 8 , so after first differentiation we get :

That the function is also increasing in the interval (-1,∞)

Now for the interval (-4,-2), we can say that the graph of the function is positive as the y value increases and then decreases but all y values are positive as illustrated in the graph.

In the interval (0,∞) the function is strictly increasing and has positive values only.

To learn more bout function visit:

brainly.com/question/21753201

#SPJ1

6 0

1 year ago