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Galina-37 [17]
3 years ago
7

Write in slope-intercept form an equation of the line that passes through the given points.

Mathematics
1 answer:
Ronch [10]3 years ago
8 0

Answer:

x=-1

Step-by-step explanation:

i think thats what you mean

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Please help, I’ll mark your answer as brainliest.
Brrunno [24]

Answers:

(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\\\(f \circ g)(2) = \sqrt{401}\\\\

========================================================

Work shown for part 1

f(x) = \sqrt{x^2-2x+2}\\\\f(g(x)) = \sqrt{(g(x))^2-2(g(x))+2}\\\\f(g(x)) = \sqrt{(-6x-7)^2-2(-6x-7)+2}\\\\f(g(x)) = \sqrt{36x^2+84x+49+12x+14+2}\\\\f(g(x)) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\

----------------------------------

Work shown for part 2

(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(2) = \sqrt{36(2)^2+96(2)+65}\\\\(f \circ g)(2) = \sqrt{401}\\\\

6 0
2 years ago
WILL MARK BRAINLIEST
Dennis_Churaev [7]
Find the area of the circle

A of circle = πr²

radius = diameter/2 = 48/2 = 24

Area = (3.14)(24)²
Area = 1808.64 in²

Hope this helps :)
6 0
4 years ago
A sports team is holding a banquet.
Amanda [17]

Answer:

$10

Step-by-step explanation:

1000 divided by 100 = 10

so $10  is the answer

then 100 tickets = $1000

PLEASE MARK BRAINLIEST AND GIVE 5 STARS.

6 0
3 years ago
I think of a number, I subtract 10 and add 2 . My answer is 20, What was my number​
Alina [70]

Answer:

28

Step-by-step explanation:

x-10+2=20

add -10 and 2 together to simplify the equation

x-8=20

add 8 to both sides to isolate x

x=28

hope this helped!

4 0
3 years ago
Two cruise ships leave port at the same time. Ship A sails north at a speed of 20 mph while Ship B sails east at a speed of 40 m
tiny-mole [99]

Answer:

a) D(t) = \[20*\sqrt{5} * t\]

b) 178.885 miles

Step-by-step explanation:

Ship A travels north at the rate of 20 mph.

Ship B travels east at the rate of 40 mph.

After t hours, Ship A is at a distance of 20t miles from the origin.

Similarly, Ship B is at a distance of 40t miles from the origin.

(a) Distance D(t) = \[\sqrt{(20t)^{2}+(40t)^{2}}\]

= \[\sqrt{400*t^{2}+1600 * (t)^{2}}\]

= \[\sqrt{2000*t^{2}}\]

= \[20*\sqrt{5} * t\]

(b) Distance between the two ships when t = 4,

= \[20*\sqrt{5} * 4\]

= \[80*\sqrt{5} \] miles

= 80 * 2.236

= 178.885 miles

8 0
3 years ago
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