Answer:
![y = -6(x - \frac{1}{2})^2 -\frac{7}{2}](https://tex.z-dn.net/?f=y%20%20%3D%20-6%28x%20-%20%5Cfrac%7B1%7D%7B2%7D%29%5E2%20-%5Cfrac%7B7%7D%7B2%7D)
Step-by-step explanation:
Given:
![y = -6x^2 + 3x + 2](https://tex.z-dn.net/?f=y%20%3D%20-6x%5E2%20%2B%203x%20%2B%202)
Required
Rewrite in vertex form
The vertex form of an equation is in form of: ![y = a(x - h)^2+ k](https://tex.z-dn.net/?f=y%20%3D%20a%28x%20-%20h%29%5E2%2B%20k)
Solving: ![y = -6x^2 + 3x + 2](https://tex.z-dn.net/?f=y%20%3D%20-6x%5E2%20%2B%203x%20%2B%202)
Subtract 2 from both sides
![y - 2 = -6x^2 + 3x + 2 - 2](https://tex.z-dn.net/?f=y%20-%202%20%3D%20-6x%5E2%20%2B%203x%20%2B%202%20-%202)
![y - 2 = -6x^2 + 3x](https://tex.z-dn.net/?f=y%20-%202%20%3D%20-6x%5E2%20%2B%203x)
Factorize expression on the right hand side by dividing through by the coefficient of x²
![y - 2 = -6(x^2 - \frac{3x}{6})](https://tex.z-dn.net/?f=y%20-%202%20%3D%20-6%28x%5E2%20-%20%5Cfrac%7B3x%7D%7B6%7D%29)
![y - 2 = -6(x^2 - \frac{x}{2})](https://tex.z-dn.net/?f=y%20-%202%20%3D%20-6%28x%5E2%20-%20%5Cfrac%7Bx%7D%7B2%7D%29)
Get a perfect square of coefficient of x; then add to both sides
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<em>Rough work</em>
The coefficient of x is ![\frac{-1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B2%7D)
It's square is ![(\frac{-1}{2})^2 = \frac{1}{4}](https://tex.z-dn.net/?f=%28%5Cfrac%7B-1%7D%7B2%7D%29%5E2%20%3D%20%5Cfrac%7B1%7D%7B4%7D)
Adding inside the bracket of
to give: ![-6(x^2 - \frac{x}{2} + \frac{1}{4})](https://tex.z-dn.net/?f=-6%28x%5E2%20-%20%5Cfrac%7Bx%7D%7B2%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D%29)
To balance the equation, the same expression must be added to the other side of the equation;
Equivalent expression is: ![-6(\frac{1}{4})](https://tex.z-dn.net/?f=-6%28%5Cfrac%7B1%7D%7B4%7D%29)
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The expression becomes
![y - 2 -6(\frac{1}{4})= -6(x^2 - \frac{x}{2} + \frac{1}{4})](https://tex.z-dn.net/?f=y%20-%202%20-6%28%5Cfrac%7B1%7D%7B4%7D%29%3D%20-6%28x%5E2%20-%20%5Cfrac%7Bx%7D%7B2%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D%29)
![y - 2 -\frac{6}{4}= -6(x^2 - \frac{x}{2} + \frac{1}{4})](https://tex.z-dn.net/?f=y%20-%202%20-%5Cfrac%7B6%7D%7B4%7D%3D%20-6%28x%5E2%20-%20%5Cfrac%7Bx%7D%7B2%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D%29)
![y - 2 -\frac{3}{2}= -6(x^2 - \frac{x}{2} + \frac{1}{4})](https://tex.z-dn.net/?f=y%20-%202%20-%5Cfrac%7B3%7D%7B2%7D%3D%20-6%28x%5E2%20-%20%5Cfrac%7Bx%7D%7B2%7D%20%2B%20%5Cfrac%7B1%7D%7B4%7D%29)
Factorize the expression on the right hand side
![y - 2 -\frac{3}{2}= -6(x - \frac{1}{2})^2](https://tex.z-dn.net/?f=y%20-%202%20-%5Cfrac%7B3%7D%7B2%7D%3D%20-6%28x%20-%20%5Cfrac%7B1%7D%7B2%7D%29%5E2)
![y - (2 +\frac{3}{2})= -6(x - \frac{1}{2})^2](https://tex.z-dn.net/?f=y%20-%20%282%20%2B%5Cfrac%7B3%7D%7B2%7D%29%3D%20-6%28x%20-%20%5Cfrac%7B1%7D%7B2%7D%29%5E2)
![y - (\frac{4+3}{2})= -6(x - \frac{1}{2})^2](https://tex.z-dn.net/?f=y%20-%20%28%5Cfrac%7B4%2B3%7D%7B2%7D%29%3D%20-6%28x%20-%20%5Cfrac%7B1%7D%7B2%7D%29%5E2)
![y - (\frac{7}{2})= -6(x - \frac{1}{2})^2](https://tex.z-dn.net/?f=y%20-%20%28%5Cfrac%7B7%7D%7B2%7D%29%3D%20-6%28x%20-%20%5Cfrac%7B1%7D%7B2%7D%29%5E2)
![y +\frac{7}{2} = -6(x - \frac{1}{2})^2](https://tex.z-dn.net/?f=y%20%20%2B%5Cfrac%7B7%7D%7B2%7D%20%3D%20-6%28x%20-%20%5Cfrac%7B1%7D%7B2%7D%29%5E2)
Make y the subject of formula
![y = -6(x - \frac{1}{2})^2 -\frac{7}{2}](https://tex.z-dn.net/?f=y%20%20%3D%20-6%28x%20-%20%5Cfrac%7B1%7D%7B2%7D%29%5E2%20-%5Cfrac%7B7%7D%7B2%7D)
<em>Solved</em>
I’m struggling too I’m sorry
14×2÷7-3+9=10
Worked it out myslef and enjoy doing math.
1)how calendar relate to math?
<span>The numbers.
You need to be able to know the date, how many days till this, so you add, how many more till this, add again, and more.
2) how cooking relate to math?
Measurements.
For example:
2 eggs
1/4 cup of flour
and
2/4 cup of milk.
You need to be able to calculate and know your measurements. Which math helps you with/
</span><span>3)how time / weather /money relate to math?
</span>Time: Numbers.
Weather: Patterns and time.
Money: Lots and lots of math.
Adding subtracting dividing multiplying and so much more.
Answer:
A
Step-by-step explanation:
They are basically wanting the value of x.
These are 2 secant lines drawn. Secant Line is a line that intersects the circle at 2 points.
To solve this, we have to use secant-secant theorem.
Secant-Secant Power Theorem tells us that if 2 secant lines are drawn from external point (here, E) to a circle, then, product of measure of one secant's external part and total secant is equal to other secants external part and whole secant.
In algebra, that is:
![(x+1)(x+1+11)=(x+4)(x+4+1)](https://tex.z-dn.net/?f=%28x%2B1%29%28x%2B1%2B11%29%3D%28x%2B4%29%28x%2B4%2B1%29)
Let's multiply and find the value of x:
![(x+1)(x+1+11)=(x+4)(x+4+1)\\(x+1)(x+12)=(x+4)(x+5)\\x^2 + 13x + 12=x^2+9x+20\\13x+12=9x+20\\13x - 9x = 20 - 12\\4x = 8\\x = 2](https://tex.z-dn.net/?f=%28x%2B1%29%28x%2B1%2B11%29%3D%28x%2B4%29%28x%2B4%2B1%29%5C%5C%28x%2B1%29%28x%2B12%29%3D%28x%2B4%29%28x%2B5%29%5C%5Cx%5E2%20%2B%2013x%20%2B%2012%3Dx%5E2%2B9x%2B20%5C%5C13x%2B12%3D9x%2B20%5C%5C13x%20-%209x%20%3D%2020%20-%2012%5C%5C4x%20%3D%208%5C%5Cx%20%3D%202)
Hence, the correct answer choice is A