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Oxana [17]
2 years ago
6

Really need help ASAP

Mathematics
1 answer:
Kipish [7]2 years ago
4 0
The third and fourth charts represent functions
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The difference of the square of a number and 40 is equal to 3 times that number. Find the positive solution.
Wewaii [24]

Answer: The answer is 8.

Step-by-step explanation: The first step is to convert the expression into figures. We shall call the unknown number Y. So if we are told “the square of a number,” that means Y squared, or better still, Y^2. Further we are told “the difference between the square of a number and 40” and that can be written as;

Y^2 - 40.

Next we are told that this expression is equal to 3 times that number (that is 3Y). That can now be written out as follows,

Y^2 - 40 = 3Y

If we move all expressions to one side of the equation, what we would have is,

Y^2 - 3Y -40 = 0

(Remember that when a positive value crosses to the other side of an equation it becomes negative and vice versa)

We now have a quadratic equation

Y^2 -3Y - 40 = 0

By factorizing we now have

(Y -8) (Y + 5) = 0

Therefore Y - 8 = 0 or

Y + 5 = 0

Hence, Y = 8 or Y = -5

Since we are asked to calculate the positive solution, Y = 8

5 0
3 years ago
The line segment joining A(6, 3) to B(–1, –4) is doubled in length by having half its length added to each end. Find the coordin
mr Goodwill [35]

Answer:

  • (9.5, 6.5) and (-4.5, -7.5)

Step-by-step explanation:

Let the extended points be A' and B' and add the point M as midpoint of AB

<u>Coordinates of M are:</u>

  • ((6 - 1)/2, (3-4)/2) = (2.5, -0.5)

Now point A is midpoint of A'M and point B is midpoint of MB'

<u>Finding the coordinates using midpoint formula:</u>

  • A' = ((2*6 - 2.5),(2*3 - (-0.5)) = (9.5, 6.5)
  • B' = ((2*(-1) - 2.5), (2*(-4) - (-0.5)) = (-4.5, -7.5)

4 0
2 years ago
Evaluate y = 7x when x = -5
borishaifa [10]

Answer:

-35

Step-by-step explanation:

7 x -5 = -35

hope this helped!! ^^

5 0
2 years ago
Henry had $1.05 in nickels and dimes. He had a total of 13
Amiraneli [1.4K]
80 dimes and 25 nickels
8 0
2 years ago
Can someone please help me with this problem asap
Kitty [74]
Where is the problem at? give me the url

6 0
2 years ago
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